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Questions: Algebra BusinessCalculus
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Find the derivative of \(\displaystyle y = \frac{\cos{\left(x \right)}}{2 x^{2} - 7 x + 4}\).
Using the quotient rule with \(\displaystyle f = \cos{\left(x \right)}\), \(\displaystyle f' = - \sin{\left(x \right)}\), \(\displaystyle g = 2 x^{2} - 7 x + 4\), and \(\displaystyle g'= 4 x - 7\) gives:
\begin{equation*} \frac{ (2 x^{2} - 7 x + 4)(- \sin{\left(x \right)}) - (\cos{\left(x \right)})(4 x - 7)}{(2 x^{2} - 7 x + 4)^2} = - \frac{2 x^{2} \sin{\left(x \right)} - 7 x \sin{\left(x \right)} + 4 x \cos{\left(x \right)} + 4 \sin{\left(x \right)} - 7 \cos{\left(x \right)}}{\left(2 x^{2} - 7 x + 4\right)^{2}} \end{equation*}
\begin{question}Find the derivative of $y = \frac{\cos{\left(x \right)}}{2 x^{2} - 7 x + 4}$. \soln{9cm}{Using the quotient rule with $f = \cos{\left(x \right)}$, $f' = - \sin{\left(x \right)}$, $g = 2 x^{2} - 7 x + 4$, and $g'= 4 x - 7$ gives:\newline \begin{equation*} \frac{ (2 x^{2} - 7 x + 4)(- \sin{\left(x \right)}) - (\cos{\left(x \right)})(4 x - 7)}{(2 x^{2} - 7 x + 4)^2} = - \frac{2 x^{2} \sin{\left(x \right)} - 7 x \sin{\left(x \right)} + 4 x \cos{\left(x \right)} + 4 \sin{\left(x \right)} - 7 \cos{\left(x \right)}}{\left(2 x^{2} - 7 x + 4\right)^{2}} \end{equation*}} \end{question}
\documentclass{article} \usepackage{tikz} \usepackage{amsmath} \usepackage[margin=2cm]{geometry} \usepackage{tcolorbox} \newcounter{ExamNumber} \newcounter{questioncount} \stepcounter{questioncount} \newenvironment{question}{{\noindent\bfseries Question \arabic{questioncount}.}}{\stepcounter{questioncount}} \renewcommand{\labelenumi}{{\bfseries (\alph{enumi})}} \newif\ifShowSolution \newcommand{\soln}[2]{% \ifShowSolution% \noindent\begin{tcolorbox}[colframe=blue,title=Solution]#2\end{tcolorbox}\else% \vspace{#1}% \fi% }% \newcommand{\hideifShowSolution}[1]{% \ifShowSolution% % \else% #1% \fi% }% \everymath{\displaystyle} \ShowSolutiontrue \begin{document}\begin{question}(10pts) The question goes here! \soln{9cm}{The solution goes here.} \end{question}\end{document}
<p> <p>Find the derivative of <img class="equation_image" title=" \displaystyle y = \frac{\cos{\left(x \right)}}{2 x^{2} - 7 x + 4} " src="/equation_images/%20%5Cdisplaystyle%20y%20%3D%20%5Cfrac%7B%5Ccos%7B%5Cleft%28x%20%5Cright%29%7D%7D%7B2%20x%5E%7B2%7D%20-%207%20x%20%2B%204%7D%20" alt="LaTeX: \displaystyle y = \frac{\cos{\left(x \right)}}{2 x^{2} - 7 x + 4} " data-equation-content=" \displaystyle y = \frac{\cos{\left(x \right)}}{2 x^{2} - 7 x + 4} " /> . </p> </p>
<p> <p>Using the quotient rule with <img class="equation_image" title=" \displaystyle f = \cos{\left(x \right)} " src="/equation_images/%20%5Cdisplaystyle%20f%20%3D%20%5Ccos%7B%5Cleft%28x%20%5Cright%29%7D%20" alt="LaTeX: \displaystyle f = \cos{\left(x \right)} " data-equation-content=" \displaystyle f = \cos{\left(x \right)} " /> , <img class="equation_image" title=" \displaystyle f' = - \sin{\left(x \right)} " src="/equation_images/%20%5Cdisplaystyle%20f%27%20%3D%20-%20%5Csin%7B%5Cleft%28x%20%5Cright%29%7D%20" alt="LaTeX: \displaystyle f' = - \sin{\left(x \right)} " data-equation-content=" \displaystyle f' = - \sin{\left(x \right)} " /> , <img class="equation_image" title=" \displaystyle g = 2 x^{2} - 7 x + 4 " src="/equation_images/%20%5Cdisplaystyle%20g%20%3D%202%20x%5E%7B2%7D%20-%207%20x%20%2B%204%20" alt="LaTeX: \displaystyle g = 2 x^{2} - 7 x + 4 " data-equation-content=" \displaystyle g = 2 x^{2} - 7 x + 4 " /> , and <img class="equation_image" title=" \displaystyle g'= 4 x - 7 " src="/equation_images/%20%5Cdisplaystyle%20g%27%3D%204%20x%20-%207%20" alt="LaTeX: \displaystyle g'= 4 x - 7 " data-equation-content=" \displaystyle g'= 4 x - 7 " /> gives:<br>
<img class="equation_image" title=" \frac{ (2 x^{2} - 7 x + 4)(- \sin{\left(x \right)}) - (\cos{\left(x \right)})(4 x - 7)}{(2 x^{2} - 7 x + 4)^2} = - \frac{2 x^{2} \sin{\left(x \right)} - 7 x \sin{\left(x \right)} + 4 x \cos{\left(x \right)} + 4 \sin{\left(x \right)} - 7 \cos{\left(x \right)}}{\left(2 x^{2} - 7 x + 4\right)^{2}} " src="/equation_images/%20%20%5Cfrac%7B%20%282%20x%5E%7B2%7D%20-%207%20x%20%2B%204%29%28-%20%5Csin%7B%5Cleft%28x%20%5Cright%29%7D%29%20-%20%28%5Ccos%7B%5Cleft%28x%20%5Cright%29%7D%29%284%20x%20-%207%29%7D%7B%282%20x%5E%7B2%7D%20-%207%20x%20%2B%204%29%5E2%7D%20%3D%20-%20%5Cfrac%7B2%20x%5E%7B2%7D%20%5Csin%7B%5Cleft%28x%20%5Cright%29%7D%20-%207%20x%20%5Csin%7B%5Cleft%28x%20%5Cright%29%7D%20%2B%204%20x%20%5Ccos%7B%5Cleft%28x%20%5Cright%29%7D%20%2B%204%20%5Csin%7B%5Cleft%28x%20%5Cright%29%7D%20-%207%20%5Ccos%7B%5Cleft%28x%20%5Cright%29%7D%7D%7B%5Cleft%282%20x%5E%7B2%7D%20-%207%20x%20%2B%204%5Cright%29%5E%7B2%7D%7D%20%20" alt="LaTeX: \frac{ (2 x^{2} - 7 x + 4)(- \sin{\left(x \right)}) - (\cos{\left(x \right)})(4 x - 7)}{(2 x^{2} - 7 x + 4)^2} = - \frac{2 x^{2} \sin{\left(x \right)} - 7 x \sin{\left(x \right)} + 4 x \cos{\left(x \right)} + 4 \sin{\left(x \right)} - 7 \cos{\left(x \right)}}{\left(2 x^{2} - 7 x + 4\right)^{2}} " data-equation-content=" \frac{ (2 x^{2} - 7 x + 4)(- \sin{\left(x \right)}) - (\cos{\left(x \right)})(4 x - 7)}{(2 x^{2} - 7 x + 4)^2} = - \frac{2 x^{2} \sin{\left(x \right)} - 7 x \sin{\left(x \right)} + 4 x \cos{\left(x \right)} + 4 \sin{\left(x \right)} - 7 \cos{\left(x \right)}}{\left(2 x^{2} - 7 x + 4\right)^{2}} " /> </p> </p>