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Questions: Algebra BusinessCalculus
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Find the derivative of \(\displaystyle f(x)=- 2 x^{5} - 12 x^{4} - 3 x^{3} + 16 x^{2} - 8 x + 13\).
Using the power rule gives \(\displaystyle f'(x)=- 10 x^{4} - 48 x^{3} - 9 x^{2} + 32 x - 8\).
\begin{question}Find the derivative of $f(x)=- 2 x^{5} - 12 x^{4} - 3 x^{3} + 16 x^{2} - 8 x + 13$. \soln{9cm}{Using the power rule gives $f'(x)=- 10 x^{4} - 48 x^{3} - 9 x^{2} + 32 x - 8$. } \end{question}
\documentclass{article} \usepackage{tikz} \usepackage{amsmath} \usepackage[margin=2cm]{geometry} \usepackage{tcolorbox} \newcounter{ExamNumber} \newcounter{questioncount} \stepcounter{questioncount} \newenvironment{question}{{\noindent\bfseries Question \arabic{questioncount}.}}{\stepcounter{questioncount}} \renewcommand{\labelenumi}{{\bfseries (\alph{enumi})}} \newif\ifShowSolution \newcommand{\soln}[2]{% \ifShowSolution% \noindent\begin{tcolorbox}[colframe=blue,title=Solution]#2\end{tcolorbox}\else% \vspace{#1}% \fi% }% \newcommand{\hideifShowSolution}[1]{% \ifShowSolution% % \else% #1% \fi% }% \everymath{\displaystyle} \ShowSolutiontrue \begin{document}\begin{question}(10pts) The question goes here! \soln{9cm}{The solution goes here.} \end{question}\end{document}
<p> <p>Find the derivative of <img class="equation_image" title=" \displaystyle f(x)=- 2 x^{5} - 12 x^{4} - 3 x^{3} + 16 x^{2} - 8 x + 13 " src="/equation_images/%20%5Cdisplaystyle%20f%28x%29%3D-%202%20x%5E%7B5%7D%20-%2012%20x%5E%7B4%7D%20-%203%20x%5E%7B3%7D%20%2B%2016%20x%5E%7B2%7D%20-%208%20x%20%2B%2013%20" alt="LaTeX: \displaystyle f(x)=- 2 x^{5} - 12 x^{4} - 3 x^{3} + 16 x^{2} - 8 x + 13 " data-equation-content=" \displaystyle f(x)=- 2 x^{5} - 12 x^{4} - 3 x^{3} + 16 x^{2} - 8 x + 13 " /> . </p> </p>
<p> <p>Using the power rule gives <img class="equation_image" title=" \displaystyle f'(x)=- 10 x^{4} - 48 x^{3} - 9 x^{2} + 32 x - 8 " src="/equation_images/%20%5Cdisplaystyle%20f%27%28x%29%3D-%2010%20x%5E%7B4%7D%20-%2048%20x%5E%7B3%7D%20-%209%20x%5E%7B2%7D%20%2B%2032%20x%20-%208%20" alt="LaTeX: \displaystyle f'(x)=- 10 x^{4} - 48 x^{3} - 9 x^{2} + 32 x - 8 " data-equation-content=" \displaystyle f'(x)=- 10 x^{4} - 48 x^{3} - 9 x^{2} + 32 x - 8 " /> . </p> </p>