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Questions: Algebra BusinessCalculus
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Find the derivative of \(\displaystyle f(x)=14 x^{3} - 13 x^{2} - 5 x - 19\).
Using the power rule gives \(\displaystyle f'(x)=42 x^{2} - 26 x - 5\).
\begin{question}Find the derivative of $f(x)=14 x^{3} - 13 x^{2} - 5 x - 19$.
\soln{9cm}{Using the power rule gives $f'(x)=42 x^{2} - 26 x - 5$. }
\end{question}
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\begin{document}\begin{question}(10pts) The question goes here!
\soln{9cm}{The solution goes here.}
\end{question}\end{document}<p> <p>Find the derivative of <img class="equation_image" title=" \displaystyle f(x)=14 x^{3} - 13 x^{2} - 5 x - 19 " src="/equation_images/%20%5Cdisplaystyle%20f%28x%29%3D14%20x%5E%7B3%7D%20-%2013%20x%5E%7B2%7D%20-%205%20x%20-%2019%20" alt="LaTeX: \displaystyle f(x)=14 x^{3} - 13 x^{2} - 5 x - 19 " data-equation-content=" \displaystyle f(x)=14 x^{3} - 13 x^{2} - 5 x - 19 " /> . </p> </p><p> <p>Using the power rule gives <img class="equation_image" title=" \displaystyle f'(x)=42 x^{2} - 26 x - 5 " src="/equation_images/%20%5Cdisplaystyle%20f%27%28x%29%3D42%20x%5E%7B2%7D%20-%2026%20x%20-%205%20" alt="LaTeX: \displaystyle f'(x)=42 x^{2} - 26 x - 5 " data-equation-content=" \displaystyle f'(x)=42 x^{2} - 26 x - 5 " /> . </p> </p>