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Calculus
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Use implicit differentiation where \(\displaystyle y\) is a function of \(\displaystyle x\) to find the derivative of \(\displaystyle 5 x^{3} \sqrt{y} - 9 \log{\left(x \right)} \sin{\left(y \right)}=48\)

Taking the derivative of both sides using implicit differentiation gives: \begin{equation*} \frac{5 x^{3} y'}{2 \sqrt{y}} + 15 x^{2} \sqrt{y} - 9 y' \log{\left(x \right)} \cos{\left(y \right)} - \frac{9 \sin{\left(y \right)}}{x} = 0 \end{equation*} Solving for \(\displaystyle y'\) gives \(\displaystyle y' = \frac{6 \left(- 5 x^{3} y + 3 \sqrt{y} \sin{\left(y \right)}\right)}{x \left(5 x^{3} - 18 \sqrt{y} \log{\left(x \right)} \cos{\left(y \right)}\right)}\)

Download \(\LaTeX\) 

\begin{question}Use implicit differentiation where $y$ is a function of $x$ to find the derivative of $5 x^{3} \sqrt{y} - 9 \log{\left(x \right)} \sin{\left(y \right)}=48$
    \soln{9cm}{Taking the derivative of both sides using implicit differentiation gives:
\begin{equation*} \frac{5 x^{3} y'}{2 \sqrt{y}} + 15 x^{2} \sqrt{y} - 9 y' \log{\left(x \right)} \cos{\left(y \right)} - \frac{9 \sin{\left(y \right)}}{x} = 0 \end{equation*}
Solving for $y'$ gives $y' = \frac{6 \left(- 5 x^{3} y + 3 \sqrt{y} \sin{\left(y \right)}\right)}{x \left(5 x^{3} - 18 \sqrt{y} \log{\left(x \right)} \cos{\left(y \right)}\right)}$}

\end{question}

Download Question and Solution Environment\(\LaTeX\)
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\begin{document}\begin{question}(10pts) The question goes here!
    \soln{9cm}{The solution goes here.}

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HTML for Canvas 
<p> <p>Use implicit differentiation where  <img class="equation_image" title=" \displaystyle y " src="/equation_images/%20%5Cdisplaystyle%20y%20" alt="LaTeX:  \displaystyle y " data-equation-content=" \displaystyle y " />  is a function of  <img class="equation_image" title=" \displaystyle x " src="/equation_images/%20%5Cdisplaystyle%20x%20" alt="LaTeX:  \displaystyle x " data-equation-content=" \displaystyle x " />  to find the derivative of  <img class="equation_image" title=" \displaystyle 5 x^{3} \sqrt{y} - 9 \log{\left(x \right)} \sin{\left(y \right)}=48 " src="/equation_images/%20%5Cdisplaystyle%205%20x%5E%7B3%7D%20%5Csqrt%7By%7D%20-%209%20%5Clog%7B%5Cleft%28x%20%5Cright%29%7D%20%5Csin%7B%5Cleft%28y%20%5Cright%29%7D%3D48%20" alt="LaTeX:  \displaystyle 5 x^{3} \sqrt{y} - 9 \log{\left(x \right)} \sin{\left(y \right)}=48 " data-equation-content=" \displaystyle 5 x^{3} \sqrt{y} - 9 \log{\left(x \right)} \sin{\left(y \right)}=48 " /> </p> </p>
HTML for Canvas
<p> <p>Taking the derivative of both sides using implicit differentiation gives:
 <img class="equation_image" title="  \frac{5 x^{3} y'}{2 \sqrt{y}} + 15 x^{2} \sqrt{y} - 9 y' \log{\left(x \right)} \cos{\left(y \right)} - \frac{9 \sin{\left(y \right)}}{x} = 0  " src="/equation_images/%20%20%5Cfrac%7B5%20x%5E%7B3%7D%20y%27%7D%7B2%20%5Csqrt%7By%7D%7D%20%2B%2015%20x%5E%7B2%7D%20%5Csqrt%7By%7D%20-%209%20y%27%20%5Clog%7B%5Cleft%28x%20%5Cright%29%7D%20%5Ccos%7B%5Cleft%28y%20%5Cright%29%7D%20-%20%5Cfrac%7B9%20%5Csin%7B%5Cleft%28y%20%5Cright%29%7D%7D%7Bx%7D%20%3D%200%20%20" alt="LaTeX:   \frac{5 x^{3} y'}{2 \sqrt{y}} + 15 x^{2} \sqrt{y} - 9 y' \log{\left(x \right)} \cos{\left(y \right)} - \frac{9 \sin{\left(y \right)}}{x} = 0  " data-equation-content="  \frac{5 x^{3} y'}{2 \sqrt{y}} + 15 x^{2} \sqrt{y} - 9 y' \log{\left(x \right)} \cos{\left(y \right)} - \frac{9 \sin{\left(y \right)}}{x} = 0  " /> 
Solving for  <img class="equation_image" title=" \displaystyle y' " src="/equation_images/%20%5Cdisplaystyle%20y%27%20" alt="LaTeX:  \displaystyle y' " data-equation-content=" \displaystyle y' " />  gives  <img class="equation_image" title=" \displaystyle y' = \frac{6 \left(- 5 x^{3} y + 3 \sqrt{y} \sin{\left(y \right)}\right)}{x \left(5 x^{3} - 18 \sqrt{y} \log{\left(x \right)} \cos{\left(y \right)}\right)} " src="/equation_images/%20%5Cdisplaystyle%20y%27%20%3D%20%5Cfrac%7B6%20%5Cleft%28-%205%20x%5E%7B3%7D%20y%20%2B%203%20%5Csqrt%7By%7D%20%5Csin%7B%5Cleft%28y%20%5Cright%29%7D%5Cright%29%7D%7Bx%20%5Cleft%285%20x%5E%7B3%7D%20-%2018%20%5Csqrt%7By%7D%20%5Clog%7B%5Cleft%28x%20%5Cright%29%7D%20%5Ccos%7B%5Cleft%28y%20%5Cright%29%7D%5Cright%29%7D%20" alt="LaTeX:  \displaystyle y' = \frac{6 \left(- 5 x^{3} y + 3 \sqrt{y} \sin{\left(y \right)}\right)}{x \left(5 x^{3} - 18 \sqrt{y} \log{\left(x \right)} \cos{\left(y \right)}\right)} " data-equation-content=" \displaystyle y' = \frac{6 \left(- 5 x^{3} y + 3 \sqrt{y} \sin{\left(y \right)}\right)}{x \left(5 x^{3} - 18 \sqrt{y} \log{\left(x \right)} \cos{\left(y \right)}\right)} " /> </p> </p>