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Calculus
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Use implicit differentiation where \(\displaystyle y\) is a function of \(\displaystyle x\) to find the derivative of \(\displaystyle - 2 x^{2} \sin{\left(y \right)} + 9 y^{2} \log{\left(x \right)}=-38\)

Taking the derivative of both sides using implicit differentiation gives: \begin{equation*} - 2 x^{2} y' \cos{\left(y \right)} - 4 x \sin{\left(y \right)} + 18 y y' \log{\left(x \right)} + \frac{9 y^{2}}{x} = 0 \end{equation*} Solving for \(\displaystyle y'\) gives \(\displaystyle y' = \frac{- 4 x^{2} \sin{\left(y \right)} + 9 y^{2}}{2 x \left(x^{2} \cos{\left(y \right)} - 9 y \log{\left(x \right)}\right)}\)

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\begin{question}Use implicit differentiation where $y$ is a function of $x$ to find the derivative of $- 2 x^{2} \sin{\left(y \right)} + 9 y^{2} \log{\left(x \right)}=-38$
    \soln{9cm}{Taking the derivative of both sides using implicit differentiation gives:
\begin{equation*} - 2 x^{2} y' \cos{\left(y \right)} - 4 x \sin{\left(y \right)} + 18 y y' \log{\left(x \right)} + \frac{9 y^{2}}{x} = 0 \end{equation*}
Solving for $y'$ gives $y' = \frac{- 4 x^{2} \sin{\left(y \right)} + 9 y^{2}}{2 x \left(x^{2} \cos{\left(y \right)} - 9 y \log{\left(x \right)}\right)}$}

\end{question}

Download Question and Solution Environment\(\LaTeX\)
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    \soln{9cm}{The solution goes here.}

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HTML for Canvas 
<p> <p>Use implicit differentiation where  <img class="equation_image" title=" \displaystyle y " src="/equation_images/%20%5Cdisplaystyle%20y%20" alt="LaTeX:  \displaystyle y " data-equation-content=" \displaystyle y " />  is a function of  <img class="equation_image" title=" \displaystyle x " src="/equation_images/%20%5Cdisplaystyle%20x%20" alt="LaTeX:  \displaystyle x " data-equation-content=" \displaystyle x " />  to find the derivative of  <img class="equation_image" title=" \displaystyle - 2 x^{2} \sin{\left(y \right)} + 9 y^{2} \log{\left(x \right)}=-38 " src="/equation_images/%20%5Cdisplaystyle%20-%202%20x%5E%7B2%7D%20%5Csin%7B%5Cleft%28y%20%5Cright%29%7D%20%2B%209%20y%5E%7B2%7D%20%5Clog%7B%5Cleft%28x%20%5Cright%29%7D%3D-38%20" alt="LaTeX:  \displaystyle - 2 x^{2} \sin{\left(y \right)} + 9 y^{2} \log{\left(x \right)}=-38 " data-equation-content=" \displaystyle - 2 x^{2} \sin{\left(y \right)} + 9 y^{2} \log{\left(x \right)}=-38 " /> </p> </p>
HTML for Canvas
<p> <p>Taking the derivative of both sides using implicit differentiation gives:
 <img class="equation_image" title="  - 2 x^{2} y' \cos{\left(y \right)} - 4 x \sin{\left(y \right)} + 18 y y' \log{\left(x \right)} + \frac{9 y^{2}}{x} = 0  " src="/equation_images/%20%20-%202%20x%5E%7B2%7D%20y%27%20%5Ccos%7B%5Cleft%28y%20%5Cright%29%7D%20-%204%20x%20%5Csin%7B%5Cleft%28y%20%5Cright%29%7D%20%2B%2018%20y%20y%27%20%5Clog%7B%5Cleft%28x%20%5Cright%29%7D%20%2B%20%5Cfrac%7B9%20y%5E%7B2%7D%7D%7Bx%7D%20%3D%200%20%20" alt="LaTeX:   - 2 x^{2} y' \cos{\left(y \right)} - 4 x \sin{\left(y \right)} + 18 y y' \log{\left(x \right)} + \frac{9 y^{2}}{x} = 0  " data-equation-content="  - 2 x^{2} y' \cos{\left(y \right)} - 4 x \sin{\left(y \right)} + 18 y y' \log{\left(x \right)} + \frac{9 y^{2}}{x} = 0  " /> 
Solving for  <img class="equation_image" title=" \displaystyle y' " src="/equation_images/%20%5Cdisplaystyle%20y%27%20" alt="LaTeX:  \displaystyle y' " data-equation-content=" \displaystyle y' " />  gives  <img class="equation_image" title=" \displaystyle y' = \frac{- 4 x^{2} \sin{\left(y \right)} + 9 y^{2}}{2 x \left(x^{2} \cos{\left(y \right)} - 9 y \log{\left(x \right)}\right)} " src="/equation_images/%20%5Cdisplaystyle%20y%27%20%3D%20%5Cfrac%7B-%204%20x%5E%7B2%7D%20%5Csin%7B%5Cleft%28y%20%5Cright%29%7D%20%2B%209%20y%5E%7B2%7D%7D%7B2%20x%20%5Cleft%28x%5E%7B2%7D%20%5Ccos%7B%5Cleft%28y%20%5Cright%29%7D%20-%209%20y%20%5Clog%7B%5Cleft%28x%20%5Cright%29%7D%5Cright%29%7D%20" alt="LaTeX:  \displaystyle y' = \frac{- 4 x^{2} \sin{\left(y \right)} + 9 y^{2}}{2 x \left(x^{2} \cos{\left(y \right)} - 9 y \log{\left(x \right)}\right)} " data-equation-content=" \displaystyle y' = \frac{- 4 x^{2} \sin{\left(y \right)} + 9 y^{2}}{2 x \left(x^{2} \cos{\left(y \right)} - 9 y \log{\left(x \right)}\right)} " /> </p> </p>