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Use Newton's method to find the first 5 approximations of the solution to the equation \(\displaystyle \sin{\left(x \right)}= \frac{131 x^{3}}{250} - 5\) using \(\displaystyle x_0=3\).
Using the formula for Newton's method gives \begin{equation*}x_{n+1} = x_{n} - \frac{- \frac{131 x_{n}^{3}}{250} + \sin{\left(x_{n} \right)} + 5}{- \frac{393 x_{n}^{2}}{250} + \cos{\left(x_{n} \right)}} \end{equation*} Using \(\displaystyle x_0 = 3\) and \(\displaystyle n = 0,1,2,3,\) and \(\displaystyle 4\) gives: \begin{equation*}x_{1} = (3.0000000000) - \frac{- \frac{131 (3.0000000000)^{3}}{250} + \sin{\left((3.0000000000) \right)} + 5}{- \frac{393 (3.0000000000)^{2}}{250} + \cos{\left((3.0000000000) \right)}} = 2.4050148992\end{equation*} \begin{equation*}x_{2} = (2.4050148992) - \frac{- \frac{131 (2.4050148992)^{3}}{250} + \sin{\left((2.4050148992) \right)} + 5}{- \frac{393 (2.4050148992)^{2}}{250} + \cos{\left((2.4050148992) \right)}} = 2.2405217072\end{equation*} \begin{equation*}x_{3} = (2.2405217072) - \frac{- \frac{131 (2.2405217072)^{3}}{250} + \sin{\left((2.2405217072) \right)} + 5}{- \frac{393 (2.2405217072)^{2}}{250} + \cos{\left((2.2405217072) \right)}} = 2.2276480503\end{equation*} \begin{equation*}x_{4} = (2.2276480503) - \frac{- \frac{131 (2.2276480503)^{3}}{250} + \sin{\left((2.2276480503) \right)} + 5}{- \frac{393 (2.2276480503)^{2}}{250} + \cos{\left((2.2276480503) \right)}} = 2.2275710384\end{equation*} \begin{equation*}x_{5} = (2.2275710384) - \frac{- \frac{131 (2.2275710384)^{3}}{250} + \sin{\left((2.2275710384) \right)} + 5}{- \frac{393 (2.2275710384)^{2}}{250} + \cos{\left((2.2275710384) \right)}} = 2.2275710356\end{equation*}
\begin{question}Use Newton's method to find the first 5 approximations of the solution to the equation $\sin{\left(x \right)}= \frac{131 x^{3}}{250} - 5$ using $x_0=3$. \soln{9cm}{Using the formula for Newton's method gives \begin{equation*}x_{n+1} = x_{n} - \frac{- \frac{131 x_{n}^{3}}{250} + \sin{\left(x_{n} \right)} + 5}{- \frac{393 x_{n}^{2}}{250} + \cos{\left(x_{n} \right)}} \end{equation*} Using $x_0 = 3$ and $n = 0,1,2,3,$ and $4$ gives: \begin{equation*}x_{1} = (3.0000000000) - \frac{- \frac{131 (3.0000000000)^{3}}{250} + \sin{\left((3.0000000000) \right)} + 5}{- \frac{393 (3.0000000000)^{2}}{250} + \cos{\left((3.0000000000) \right)}} = 2.4050148992\end{equation*} \begin{equation*}x_{2} = (2.4050148992) - \frac{- \frac{131 (2.4050148992)^{3}}{250} + \sin{\left((2.4050148992) \right)} + 5}{- \frac{393 (2.4050148992)^{2}}{250} + \cos{\left((2.4050148992) \right)}} = 2.2405217072\end{equation*} \begin{equation*}x_{3} = (2.2405217072) - \frac{- \frac{131 (2.2405217072)^{3}}{250} + \sin{\left((2.2405217072) \right)} + 5}{- \frac{393 (2.2405217072)^{2}}{250} + \cos{\left((2.2405217072) \right)}} = 2.2276480503\end{equation*} \begin{equation*}x_{4} = (2.2276480503) - \frac{- \frac{131 (2.2276480503)^{3}}{250} + \sin{\left((2.2276480503) \right)} + 5}{- \frac{393 (2.2276480503)^{2}}{250} + \cos{\left((2.2276480503) \right)}} = 2.2275710384\end{equation*} \begin{equation*}x_{5} = (2.2275710384) - \frac{- \frac{131 (2.2275710384)^{3}}{250} + \sin{\left((2.2275710384) \right)} + 5}{- \frac{393 (2.2275710384)^{2}}{250} + \cos{\left((2.2275710384) \right)}} = 2.2275710356\end{equation*} } \end{question}
\documentclass{article} \usepackage{tikz} \usepackage{amsmath} \usepackage[margin=2cm]{geometry} \usepackage{tcolorbox} \newcounter{ExamNumber} \newcounter{questioncount} \stepcounter{questioncount} \newenvironment{question}{{\noindent\bfseries Question \arabic{questioncount}.}}{\stepcounter{questioncount}} \renewcommand{\labelenumi}{{\bfseries (\alph{enumi})}} \newif\ifShowSolution \newcommand{\soln}[2]{% \ifShowSolution% \noindent\begin{tcolorbox}[colframe=blue,title=Solution]#2\end{tcolorbox}\else% \vspace{#1}% \fi% }% \newcommand{\hideifShowSolution}[1]{% \ifShowSolution% % \else% #1% \fi% }% \everymath{\displaystyle} \ShowSolutiontrue \begin{document}\begin{question}(10pts) The question goes here! \soln{9cm}{The solution goes here.} \end{question}\end{document}
<p> <p>Use Newton's method to find the first 5 approximations of the solution to the equation <img class="equation_image" title=" \displaystyle \sin{\left(x \right)}= \frac{131 x^{3}}{250} - 5 " src="/equation_images/%20%5Cdisplaystyle%20%5Csin%7B%5Cleft%28x%20%5Cright%29%7D%3D%20%5Cfrac%7B131%20x%5E%7B3%7D%7D%7B250%7D%20-%205%20" alt="LaTeX: \displaystyle \sin{\left(x \right)}= \frac{131 x^{3}}{250} - 5 " data-equation-content=" \displaystyle \sin{\left(x \right)}= \frac{131 x^{3}}{250} - 5 " /> using <img class="equation_image" title=" \displaystyle x_0=3 " src="/equation_images/%20%5Cdisplaystyle%20x_0%3D3%20" alt="LaTeX: \displaystyle x_0=3 " data-equation-content=" \displaystyle x_0=3 " /> . </p> </p>
<p> <p>Using the formula for Newton's method gives
<img class="equation_image" title=" x_{n+1} = x_{n} - \frac{- \frac{131 x_{n}^{3}}{250} + \sin{\left(x_{n} \right)} + 5}{- \frac{393 x_{n}^{2}}{250} + \cos{\left(x_{n} \right)}} " src="/equation_images/%20x_%7Bn%2B1%7D%20%3D%20%20x_%7Bn%7D%20-%20%5Cfrac%7B-%20%5Cfrac%7B131%20x_%7Bn%7D%5E%7B3%7D%7D%7B250%7D%20%2B%20%5Csin%7B%5Cleft%28x_%7Bn%7D%20%5Cright%29%7D%20%2B%205%7D%7B-%20%5Cfrac%7B393%20x_%7Bn%7D%5E%7B2%7D%7D%7B250%7D%20%2B%20%5Ccos%7B%5Cleft%28x_%7Bn%7D%20%5Cright%29%7D%7D%20%20%20" alt="LaTeX: x_{n+1} = x_{n} - \frac{- \frac{131 x_{n}^{3}}{250} + \sin{\left(x_{n} \right)} + 5}{- \frac{393 x_{n}^{2}}{250} + \cos{\left(x_{n} \right)}} " data-equation-content=" x_{n+1} = x_{n} - \frac{- \frac{131 x_{n}^{3}}{250} + \sin{\left(x_{n} \right)} + 5}{- \frac{393 x_{n}^{2}}{250} + \cos{\left(x_{n} \right)}} " />
Using <img class="equation_image" title=" \displaystyle x_0 = 3 " src="/equation_images/%20%5Cdisplaystyle%20x_0%20%3D%203%20" alt="LaTeX: \displaystyle x_0 = 3 " data-equation-content=" \displaystyle x_0 = 3 " /> and <img class="equation_image" title=" \displaystyle n = 0,1,2,3, " src="/equation_images/%20%5Cdisplaystyle%20n%20%3D%200%2C1%2C2%2C3%2C%20" alt="LaTeX: \displaystyle n = 0,1,2,3, " data-equation-content=" \displaystyle n = 0,1,2,3, " /> and <img class="equation_image" title=" \displaystyle 4 " src="/equation_images/%20%5Cdisplaystyle%204%20" alt="LaTeX: \displaystyle 4 " data-equation-content=" \displaystyle 4 " /> gives:
<img class="equation_image" title=" x_{1} = (3.0000000000) - \frac{- \frac{131 (3.0000000000)^{3}}{250} + \sin{\left((3.0000000000) \right)} + 5}{- \frac{393 (3.0000000000)^{2}}{250} + \cos{\left((3.0000000000) \right)}} = 2.4050148992 " src="/equation_images/%20x_%7B1%7D%20%3D%20%20%283.0000000000%29%20-%20%5Cfrac%7B-%20%5Cfrac%7B131%20%283.0000000000%29%5E%7B3%7D%7D%7B250%7D%20%2B%20%5Csin%7B%5Cleft%28%283.0000000000%29%20%5Cright%29%7D%20%2B%205%7D%7B-%20%5Cfrac%7B393%20%283.0000000000%29%5E%7B2%7D%7D%7B250%7D%20%2B%20%5Ccos%7B%5Cleft%28%283.0000000000%29%20%5Cright%29%7D%7D%20%3D%202.4050148992%20" alt="LaTeX: x_{1} = (3.0000000000) - \frac{- \frac{131 (3.0000000000)^{3}}{250} + \sin{\left((3.0000000000) \right)} + 5}{- \frac{393 (3.0000000000)^{2}}{250} + \cos{\left((3.0000000000) \right)}} = 2.4050148992 " data-equation-content=" x_{1} = (3.0000000000) - \frac{- \frac{131 (3.0000000000)^{3}}{250} + \sin{\left((3.0000000000) \right)} + 5}{- \frac{393 (3.0000000000)^{2}}{250} + \cos{\left((3.0000000000) \right)}} = 2.4050148992 " />
<img class="equation_image" title=" x_{2} = (2.4050148992) - \frac{- \frac{131 (2.4050148992)^{3}}{250} + \sin{\left((2.4050148992) \right)} + 5}{- \frac{393 (2.4050148992)^{2}}{250} + \cos{\left((2.4050148992) \right)}} = 2.2405217072 " src="/equation_images/%20x_%7B2%7D%20%3D%20%20%282.4050148992%29%20-%20%5Cfrac%7B-%20%5Cfrac%7B131%20%282.4050148992%29%5E%7B3%7D%7D%7B250%7D%20%2B%20%5Csin%7B%5Cleft%28%282.4050148992%29%20%5Cright%29%7D%20%2B%205%7D%7B-%20%5Cfrac%7B393%20%282.4050148992%29%5E%7B2%7D%7D%7B250%7D%20%2B%20%5Ccos%7B%5Cleft%28%282.4050148992%29%20%5Cright%29%7D%7D%20%3D%202.2405217072%20" alt="LaTeX: x_{2} = (2.4050148992) - \frac{- \frac{131 (2.4050148992)^{3}}{250} + \sin{\left((2.4050148992) \right)} + 5}{- \frac{393 (2.4050148992)^{2}}{250} + \cos{\left((2.4050148992) \right)}} = 2.2405217072 " data-equation-content=" x_{2} = (2.4050148992) - \frac{- \frac{131 (2.4050148992)^{3}}{250} + \sin{\left((2.4050148992) \right)} + 5}{- \frac{393 (2.4050148992)^{2}}{250} + \cos{\left((2.4050148992) \right)}} = 2.2405217072 " />
<img class="equation_image" title=" x_{3} = (2.2405217072) - \frac{- \frac{131 (2.2405217072)^{3}}{250} + \sin{\left((2.2405217072) \right)} + 5}{- \frac{393 (2.2405217072)^{2}}{250} + \cos{\left((2.2405217072) \right)}} = 2.2276480503 " src="/equation_images/%20x_%7B3%7D%20%3D%20%20%282.2405217072%29%20-%20%5Cfrac%7B-%20%5Cfrac%7B131%20%282.2405217072%29%5E%7B3%7D%7D%7B250%7D%20%2B%20%5Csin%7B%5Cleft%28%282.2405217072%29%20%5Cright%29%7D%20%2B%205%7D%7B-%20%5Cfrac%7B393%20%282.2405217072%29%5E%7B2%7D%7D%7B250%7D%20%2B%20%5Ccos%7B%5Cleft%28%282.2405217072%29%20%5Cright%29%7D%7D%20%3D%202.2276480503%20" alt="LaTeX: x_{3} = (2.2405217072) - \frac{- \frac{131 (2.2405217072)^{3}}{250} + \sin{\left((2.2405217072) \right)} + 5}{- \frac{393 (2.2405217072)^{2}}{250} + \cos{\left((2.2405217072) \right)}} = 2.2276480503 " data-equation-content=" x_{3} = (2.2405217072) - \frac{- \frac{131 (2.2405217072)^{3}}{250} + \sin{\left((2.2405217072) \right)} + 5}{- \frac{393 (2.2405217072)^{2}}{250} + \cos{\left((2.2405217072) \right)}} = 2.2276480503 " />
<img class="equation_image" title=" x_{4} = (2.2276480503) - \frac{- \frac{131 (2.2276480503)^{3}}{250} + \sin{\left((2.2276480503) \right)} + 5}{- \frac{393 (2.2276480503)^{2}}{250} + \cos{\left((2.2276480503) \right)}} = 2.2275710384 " src="/equation_images/%20x_%7B4%7D%20%3D%20%20%282.2276480503%29%20-%20%5Cfrac%7B-%20%5Cfrac%7B131%20%282.2276480503%29%5E%7B3%7D%7D%7B250%7D%20%2B%20%5Csin%7B%5Cleft%28%282.2276480503%29%20%5Cright%29%7D%20%2B%205%7D%7B-%20%5Cfrac%7B393%20%282.2276480503%29%5E%7B2%7D%7D%7B250%7D%20%2B%20%5Ccos%7B%5Cleft%28%282.2276480503%29%20%5Cright%29%7D%7D%20%3D%202.2275710384%20" alt="LaTeX: x_{4} = (2.2276480503) - \frac{- \frac{131 (2.2276480503)^{3}}{250} + \sin{\left((2.2276480503) \right)} + 5}{- \frac{393 (2.2276480503)^{2}}{250} + \cos{\left((2.2276480503) \right)}} = 2.2275710384 " data-equation-content=" x_{4} = (2.2276480503) - \frac{- \frac{131 (2.2276480503)^{3}}{250} + \sin{\left((2.2276480503) \right)} + 5}{- \frac{393 (2.2276480503)^{2}}{250} + \cos{\left((2.2276480503) \right)}} = 2.2275710384 " />
<img class="equation_image" title=" x_{5} = (2.2275710384) - \frac{- \frac{131 (2.2275710384)^{3}}{250} + \sin{\left((2.2275710384) \right)} + 5}{- \frac{393 (2.2275710384)^{2}}{250} + \cos{\left((2.2275710384) \right)}} = 2.2275710356 " src="/equation_images/%20x_%7B5%7D%20%3D%20%20%282.2275710384%29%20-%20%5Cfrac%7B-%20%5Cfrac%7B131%20%282.2275710384%29%5E%7B3%7D%7D%7B250%7D%20%2B%20%5Csin%7B%5Cleft%28%282.2275710384%29%20%5Cright%29%7D%20%2B%205%7D%7B-%20%5Cfrac%7B393%20%282.2275710384%29%5E%7B2%7D%7D%7B250%7D%20%2B%20%5Ccos%7B%5Cleft%28%282.2275710384%29%20%5Cright%29%7D%7D%20%3D%202.2275710356%20" alt="LaTeX: x_{5} = (2.2275710384) - \frac{- \frac{131 (2.2275710384)^{3}}{250} + \sin{\left((2.2275710384) \right)} + 5}{- \frac{393 (2.2275710384)^{2}}{250} + \cos{\left((2.2275710384) \right)}} = 2.2275710356 " data-equation-content=" x_{5} = (2.2275710384) - \frac{- \frac{131 (2.2275710384)^{3}}{250} + \sin{\left((2.2275710384) \right)} + 5}{- \frac{393 (2.2275710384)^{2}}{250} + \cos{\left((2.2275710384) \right)}} = 2.2275710356 " />
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