\(\text{www.the}\beta\text{etafunction.com}\)
Home
Login
Questions: Algebra BusinessCalculus

Please login to create an exam or a quiz.

Calculus
Applications of Derivatives
New Random

Use Newton's method to find the first 5 approximations of the solution to the equation \(\displaystyle \sin{\left(x \right)}= \frac{131 x^{3}}{250} - 5\) using \(\displaystyle x_0=3\).


Using the formula for Newton's method gives \begin{equation*}x_{n+1} = x_{n} - \frac{- \frac{131 x_{n}^{3}}{250} + \sin{\left(x_{n} \right)} + 5}{- \frac{393 x_{n}^{2}}{250} + \cos{\left(x_{n} \right)}} \end{equation*} Using \(\displaystyle x_0 = 3\) and \(\displaystyle n = 0,1,2,3,\) and \(\displaystyle 4\) gives: \begin{equation*}x_{1} = (3.0000000000) - \frac{- \frac{131 (3.0000000000)^{3}}{250} + \sin{\left((3.0000000000) \right)} + 5}{- \frac{393 (3.0000000000)^{2}}{250} + \cos{\left((3.0000000000) \right)}} = 2.4050148992\end{equation*} \begin{equation*}x_{2} = (2.4050148992) - \frac{- \frac{131 (2.4050148992)^{3}}{250} + \sin{\left((2.4050148992) \right)} + 5}{- \frac{393 (2.4050148992)^{2}}{250} + \cos{\left((2.4050148992) \right)}} = 2.2405217072\end{equation*} \begin{equation*}x_{3} = (2.2405217072) - \frac{- \frac{131 (2.2405217072)^{3}}{250} + \sin{\left((2.2405217072) \right)} + 5}{- \frac{393 (2.2405217072)^{2}}{250} + \cos{\left((2.2405217072) \right)}} = 2.2276480503\end{equation*} \begin{equation*}x_{4} = (2.2276480503) - \frac{- \frac{131 (2.2276480503)^{3}}{250} + \sin{\left((2.2276480503) \right)} + 5}{- \frac{393 (2.2276480503)^{2}}{250} + \cos{\left((2.2276480503) \right)}} = 2.2275710384\end{equation*} \begin{equation*}x_{5} = (2.2275710384) - \frac{- \frac{131 (2.2275710384)^{3}}{250} + \sin{\left((2.2275710384) \right)} + 5}{- \frac{393 (2.2275710384)^{2}}{250} + \cos{\left((2.2275710384) \right)}} = 2.2275710356\end{equation*}

Download \(\LaTeX\)

\begin{question}Use Newton's method to find the first 5 approximations of the solution to the equation $\sin{\left(x \right)}= \frac{131 x^{3}}{250} - 5$ using $x_0=3$. 
    \soln{9cm}{Using the formula for Newton's method gives
\begin{equation*}x_{n+1} =  x_{n} - \frac{- \frac{131 x_{n}^{3}}{250} + \sin{\left(x_{n} \right)} + 5}{- \frac{393 x_{n}^{2}}{250} + \cos{\left(x_{n} \right)}}  \end{equation*}
Using $x_0 = 3$ and $n = 0,1,2,3,$ and $4$ gives:
\begin{equation*}x_{1} =  (3.0000000000) - \frac{- \frac{131 (3.0000000000)^{3}}{250} + \sin{\left((3.0000000000) \right)} + 5}{- \frac{393 (3.0000000000)^{2}}{250} + \cos{\left((3.0000000000) \right)}} = 2.4050148992\end{equation*}
\begin{equation*}x_{2} =  (2.4050148992) - \frac{- \frac{131 (2.4050148992)^{3}}{250} + \sin{\left((2.4050148992) \right)} + 5}{- \frac{393 (2.4050148992)^{2}}{250} + \cos{\left((2.4050148992) \right)}} = 2.2405217072\end{equation*}
\begin{equation*}x_{3} =  (2.2405217072) - \frac{- \frac{131 (2.2405217072)^{3}}{250} + \sin{\left((2.2405217072) \right)} + 5}{- \frac{393 (2.2405217072)^{2}}{250} + \cos{\left((2.2405217072) \right)}} = 2.2276480503\end{equation*}
\begin{equation*}x_{4} =  (2.2276480503) - \frac{- \frac{131 (2.2276480503)^{3}}{250} + \sin{\left((2.2276480503) \right)} + 5}{- \frac{393 (2.2276480503)^{2}}{250} + \cos{\left((2.2276480503) \right)}} = 2.2275710384\end{equation*}
\begin{equation*}x_{5} =  (2.2275710384) - \frac{- \frac{131 (2.2275710384)^{3}}{250} + \sin{\left((2.2275710384) \right)} + 5}{- \frac{393 (2.2275710384)^{2}}{250} + \cos{\left((2.2275710384) \right)}} = 2.2275710356\end{equation*}
}

\end{question}

Download Question and Solution Environment\(\LaTeX\)
\documentclass{article}
\usepackage{tikz}
\usepackage{amsmath}
\usepackage[margin=2cm]{geometry}
\usepackage{tcolorbox}

\newcounter{ExamNumber}
\newcounter{questioncount}
\stepcounter{questioncount}

\newenvironment{question}{{\noindent\bfseries Question \arabic{questioncount}.}}{\stepcounter{questioncount}}
\renewcommand{\labelenumi}{{\bfseries (\alph{enumi})}}

\newif\ifShowSolution
\newcommand{\soln}[2]{%
\ifShowSolution%
\noindent\begin{tcolorbox}[colframe=blue,title=Solution]#2\end{tcolorbox}\else%
\vspace{#1}%
\fi%
}%
\newcommand{\hideifShowSolution}[1]{%
\ifShowSolution%
%
\else%
#1%
\fi%
}%
\everymath{\displaystyle}
\ShowSolutiontrue

\begin{document}\begin{question}(10pts) The question goes here!
    \soln{9cm}{The solution goes here.}

\end{question}\end{document}
HTML for Canvas
<p> <p>Use Newton's method to find the first 5 approximations of the solution to the equation  <img class="equation_image" title=" \displaystyle \sin{\left(x \right)}= \frac{131 x^{3}}{250} - 5 " src="/equation_images/%20%5Cdisplaystyle%20%5Csin%7B%5Cleft%28x%20%5Cright%29%7D%3D%20%5Cfrac%7B131%20x%5E%7B3%7D%7D%7B250%7D%20-%205%20" alt="LaTeX:  \displaystyle \sin{\left(x \right)}= \frac{131 x^{3}}{250} - 5 " data-equation-content=" \displaystyle \sin{\left(x \right)}= \frac{131 x^{3}}{250} - 5 " />  using  <img class="equation_image" title=" \displaystyle x_0=3 " src="/equation_images/%20%5Cdisplaystyle%20x_0%3D3%20" alt="LaTeX:  \displaystyle x_0=3 " data-equation-content=" \displaystyle x_0=3 " /> . </p> </p>
HTML for Canvas
<p> <p>Using the formula for Newton's method gives
 <img class="equation_image" title=" x_{n+1} =  x_{n} - \frac{- \frac{131 x_{n}^{3}}{250} + \sin{\left(x_{n} \right)} + 5}{- \frac{393 x_{n}^{2}}{250} + \cos{\left(x_{n} \right)}}   " src="/equation_images/%20x_%7Bn%2B1%7D%20%3D%20%20x_%7Bn%7D%20-%20%5Cfrac%7B-%20%5Cfrac%7B131%20x_%7Bn%7D%5E%7B3%7D%7D%7B250%7D%20%2B%20%5Csin%7B%5Cleft%28x_%7Bn%7D%20%5Cright%29%7D%20%2B%205%7D%7B-%20%5Cfrac%7B393%20x_%7Bn%7D%5E%7B2%7D%7D%7B250%7D%20%2B%20%5Ccos%7B%5Cleft%28x_%7Bn%7D%20%5Cright%29%7D%7D%20%20%20" alt="LaTeX:  x_{n+1} =  x_{n} - \frac{- \frac{131 x_{n}^{3}}{250} + \sin{\left(x_{n} \right)} + 5}{- \frac{393 x_{n}^{2}}{250} + \cos{\left(x_{n} \right)}}   " data-equation-content=" x_{n+1} =  x_{n} - \frac{- \frac{131 x_{n}^{3}}{250} + \sin{\left(x_{n} \right)} + 5}{- \frac{393 x_{n}^{2}}{250} + \cos{\left(x_{n} \right)}}   " /> 
Using  <img class="equation_image" title=" \displaystyle x_0 = 3 " src="/equation_images/%20%5Cdisplaystyle%20x_0%20%3D%203%20" alt="LaTeX:  \displaystyle x_0 = 3 " data-equation-content=" \displaystyle x_0 = 3 " />  and  <img class="equation_image" title=" \displaystyle n = 0,1,2,3, " src="/equation_images/%20%5Cdisplaystyle%20n%20%3D%200%2C1%2C2%2C3%2C%20" alt="LaTeX:  \displaystyle n = 0,1,2,3, " data-equation-content=" \displaystyle n = 0,1,2,3, " />  and  <img class="equation_image" title=" \displaystyle 4 " src="/equation_images/%20%5Cdisplaystyle%204%20" alt="LaTeX:  \displaystyle 4 " data-equation-content=" \displaystyle 4 " />  gives:
 <img class="equation_image" title=" x_{1} =  (3.0000000000) - \frac{- \frac{131 (3.0000000000)^{3}}{250} + \sin{\left((3.0000000000) \right)} + 5}{- \frac{393 (3.0000000000)^{2}}{250} + \cos{\left((3.0000000000) \right)}} = 2.4050148992 " src="/equation_images/%20x_%7B1%7D%20%3D%20%20%283.0000000000%29%20-%20%5Cfrac%7B-%20%5Cfrac%7B131%20%283.0000000000%29%5E%7B3%7D%7D%7B250%7D%20%2B%20%5Csin%7B%5Cleft%28%283.0000000000%29%20%5Cright%29%7D%20%2B%205%7D%7B-%20%5Cfrac%7B393%20%283.0000000000%29%5E%7B2%7D%7D%7B250%7D%20%2B%20%5Ccos%7B%5Cleft%28%283.0000000000%29%20%5Cright%29%7D%7D%20%3D%202.4050148992%20" alt="LaTeX:  x_{1} =  (3.0000000000) - \frac{- \frac{131 (3.0000000000)^{3}}{250} + \sin{\left((3.0000000000) \right)} + 5}{- \frac{393 (3.0000000000)^{2}}{250} + \cos{\left((3.0000000000) \right)}} = 2.4050148992 " data-equation-content=" x_{1} =  (3.0000000000) - \frac{- \frac{131 (3.0000000000)^{3}}{250} + \sin{\left((3.0000000000) \right)} + 5}{- \frac{393 (3.0000000000)^{2}}{250} + \cos{\left((3.0000000000) \right)}} = 2.4050148992 " /> 
 <img class="equation_image" title=" x_{2} =  (2.4050148992) - \frac{- \frac{131 (2.4050148992)^{3}}{250} + \sin{\left((2.4050148992) \right)} + 5}{- \frac{393 (2.4050148992)^{2}}{250} + \cos{\left((2.4050148992) \right)}} = 2.2405217072 " src="/equation_images/%20x_%7B2%7D%20%3D%20%20%282.4050148992%29%20-%20%5Cfrac%7B-%20%5Cfrac%7B131%20%282.4050148992%29%5E%7B3%7D%7D%7B250%7D%20%2B%20%5Csin%7B%5Cleft%28%282.4050148992%29%20%5Cright%29%7D%20%2B%205%7D%7B-%20%5Cfrac%7B393%20%282.4050148992%29%5E%7B2%7D%7D%7B250%7D%20%2B%20%5Ccos%7B%5Cleft%28%282.4050148992%29%20%5Cright%29%7D%7D%20%3D%202.2405217072%20" alt="LaTeX:  x_{2} =  (2.4050148992) - \frac{- \frac{131 (2.4050148992)^{3}}{250} + \sin{\left((2.4050148992) \right)} + 5}{- \frac{393 (2.4050148992)^{2}}{250} + \cos{\left((2.4050148992) \right)}} = 2.2405217072 " data-equation-content=" x_{2} =  (2.4050148992) - \frac{- \frac{131 (2.4050148992)^{3}}{250} + \sin{\left((2.4050148992) \right)} + 5}{- \frac{393 (2.4050148992)^{2}}{250} + \cos{\left((2.4050148992) \right)}} = 2.2405217072 " /> 
 <img class="equation_image" title=" x_{3} =  (2.2405217072) - \frac{- \frac{131 (2.2405217072)^{3}}{250} + \sin{\left((2.2405217072) \right)} + 5}{- \frac{393 (2.2405217072)^{2}}{250} + \cos{\left((2.2405217072) \right)}} = 2.2276480503 " src="/equation_images/%20x_%7B3%7D%20%3D%20%20%282.2405217072%29%20-%20%5Cfrac%7B-%20%5Cfrac%7B131%20%282.2405217072%29%5E%7B3%7D%7D%7B250%7D%20%2B%20%5Csin%7B%5Cleft%28%282.2405217072%29%20%5Cright%29%7D%20%2B%205%7D%7B-%20%5Cfrac%7B393%20%282.2405217072%29%5E%7B2%7D%7D%7B250%7D%20%2B%20%5Ccos%7B%5Cleft%28%282.2405217072%29%20%5Cright%29%7D%7D%20%3D%202.2276480503%20" alt="LaTeX:  x_{3} =  (2.2405217072) - \frac{- \frac{131 (2.2405217072)^{3}}{250} + \sin{\left((2.2405217072) \right)} + 5}{- \frac{393 (2.2405217072)^{2}}{250} + \cos{\left((2.2405217072) \right)}} = 2.2276480503 " data-equation-content=" x_{3} =  (2.2405217072) - \frac{- \frac{131 (2.2405217072)^{3}}{250} + \sin{\left((2.2405217072) \right)} + 5}{- \frac{393 (2.2405217072)^{2}}{250} + \cos{\left((2.2405217072) \right)}} = 2.2276480503 " /> 
 <img class="equation_image" title=" x_{4} =  (2.2276480503) - \frac{- \frac{131 (2.2276480503)^{3}}{250} + \sin{\left((2.2276480503) \right)} + 5}{- \frac{393 (2.2276480503)^{2}}{250} + \cos{\left((2.2276480503) \right)}} = 2.2275710384 " src="/equation_images/%20x_%7B4%7D%20%3D%20%20%282.2276480503%29%20-%20%5Cfrac%7B-%20%5Cfrac%7B131%20%282.2276480503%29%5E%7B3%7D%7D%7B250%7D%20%2B%20%5Csin%7B%5Cleft%28%282.2276480503%29%20%5Cright%29%7D%20%2B%205%7D%7B-%20%5Cfrac%7B393%20%282.2276480503%29%5E%7B2%7D%7D%7B250%7D%20%2B%20%5Ccos%7B%5Cleft%28%282.2276480503%29%20%5Cright%29%7D%7D%20%3D%202.2275710384%20" alt="LaTeX:  x_{4} =  (2.2276480503) - \frac{- \frac{131 (2.2276480503)^{3}}{250} + \sin{\left((2.2276480503) \right)} + 5}{- \frac{393 (2.2276480503)^{2}}{250} + \cos{\left((2.2276480503) \right)}} = 2.2275710384 " data-equation-content=" x_{4} =  (2.2276480503) - \frac{- \frac{131 (2.2276480503)^{3}}{250} + \sin{\left((2.2276480503) \right)} + 5}{- \frac{393 (2.2276480503)^{2}}{250} + \cos{\left((2.2276480503) \right)}} = 2.2275710384 " /> 
 <img class="equation_image" title=" x_{5} =  (2.2275710384) - \frac{- \frac{131 (2.2275710384)^{3}}{250} + \sin{\left((2.2275710384) \right)} + 5}{- \frac{393 (2.2275710384)^{2}}{250} + \cos{\left((2.2275710384) \right)}} = 2.2275710356 " src="/equation_images/%20x_%7B5%7D%20%3D%20%20%282.2275710384%29%20-%20%5Cfrac%7B-%20%5Cfrac%7B131%20%282.2275710384%29%5E%7B3%7D%7D%7B250%7D%20%2B%20%5Csin%7B%5Cleft%28%282.2275710384%29%20%5Cright%29%7D%20%2B%205%7D%7B-%20%5Cfrac%7B393%20%282.2275710384%29%5E%7B2%7D%7D%7B250%7D%20%2B%20%5Ccos%7B%5Cleft%28%282.2275710384%29%20%5Cright%29%7D%7D%20%3D%202.2275710356%20" alt="LaTeX:  x_{5} =  (2.2275710384) - \frac{- \frac{131 (2.2275710384)^{3}}{250} + \sin{\left((2.2275710384) \right)} + 5}{- \frac{393 (2.2275710384)^{2}}{250} + \cos{\left((2.2275710384) \right)}} = 2.2275710356 " data-equation-content=" x_{5} =  (2.2275710384) - \frac{- \frac{131 (2.2275710384)^{3}}{250} + \sin{\left((2.2275710384) \right)} + 5}{- \frac{393 (2.2275710384)^{2}}{250} + \cos{\left((2.2275710384) \right)}} = 2.2275710356 " /> 
</p> </p>