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Find the anti-derivative of \(\displaystyle f(x) = \frac{- 9 x^{3} - 9 x^{2} - 2 x - 8}{\sqrt[4]{x}}\)
Using termwise division gives \(\displaystyle f(x) = - 9 x^{\frac{11}{4}} - 9 x^{\frac{7}{4}} - 2 x^{\frac{3}{4}} - \frac{8}{\sqrt[4]{x}}\). Finding the antiderivative of each term gives \(\displaystyle F(x) = - \frac{12 x^{\frac{15}{4}}}{5} - \frac{36 x^{\frac{11}{4}}}{11} - \frac{8 x^{\frac{7}{4}}}{7} - \frac{32 x^{\frac{3}{4}}}{3} + C\)
\begin{question}Find the anti-derivative of $f(x) = \frac{- 9 x^{3} - 9 x^{2} - 2 x - 8}{\sqrt[4]{x}}$ \soln{9cm}{Using termwise division gives $f(x) = - 9 x^{\frac{11}{4}} - 9 x^{\frac{7}{4}} - 2 x^{\frac{3}{4}} - \frac{8}{\sqrt[4]{x}}$. Finding the antiderivative of each term gives $F(x) = - \frac{12 x^{\frac{15}{4}}}{5} - \frac{36 x^{\frac{11}{4}}}{11} - \frac{8 x^{\frac{7}{4}}}{7} - \frac{32 x^{\frac{3}{4}}}{3} + C$} \end{question}
\documentclass{article} \usepackage{tikz} \usepackage{amsmath} \usepackage[margin=2cm]{geometry} \usepackage{tcolorbox} \newcounter{ExamNumber} \newcounter{questioncount} \stepcounter{questioncount} \newenvironment{question}{{\noindent\bfseries Question \arabic{questioncount}.}}{\stepcounter{questioncount}} \renewcommand{\labelenumi}{{\bfseries (\alph{enumi})}} \newif\ifShowSolution \newcommand{\soln}[2]{% \ifShowSolution% \noindent\begin{tcolorbox}[colframe=blue,title=Solution]#2\end{tcolorbox}\else% \vspace{#1}% \fi% }% \newcommand{\hideifShowSolution}[1]{% \ifShowSolution% % \else% #1% \fi% }% \everymath{\displaystyle} \ShowSolutiontrue \begin{document}\begin{question}(10pts) The question goes here! \soln{9cm}{The solution goes here.} \end{question}\end{document}
<p> <p>Find the anti-derivative of <img class="equation_image" title=" \displaystyle f(x) = \frac{- 9 x^{3} - 9 x^{2} - 2 x - 8}{\sqrt[4]{x}} " src="/equation_images/%20%5Cdisplaystyle%20f%28x%29%20%3D%20%5Cfrac%7B-%209%20x%5E%7B3%7D%20-%209%20x%5E%7B2%7D%20-%202%20x%20-%208%7D%7B%5Csqrt%5B4%5D%7Bx%7D%7D%20" alt="LaTeX: \displaystyle f(x) = \frac{- 9 x^{3} - 9 x^{2} - 2 x - 8}{\sqrt[4]{x}} " data-equation-content=" \displaystyle f(x) = \frac{- 9 x^{3} - 9 x^{2} - 2 x - 8}{\sqrt[4]{x}} " /> </p> </p>
<p> <p>Using termwise division gives <img class="equation_image" title=" \displaystyle f(x) = - 9 x^{\frac{11}{4}} - 9 x^{\frac{7}{4}} - 2 x^{\frac{3}{4}} - \frac{8}{\sqrt[4]{x}} " src="/equation_images/%20%5Cdisplaystyle%20f%28x%29%20%3D%20-%209%20x%5E%7B%5Cfrac%7B11%7D%7B4%7D%7D%20-%209%20x%5E%7B%5Cfrac%7B7%7D%7B4%7D%7D%20-%202%20x%5E%7B%5Cfrac%7B3%7D%7B4%7D%7D%20-%20%5Cfrac%7B8%7D%7B%5Csqrt%5B4%5D%7Bx%7D%7D%20" alt="LaTeX: \displaystyle f(x) = - 9 x^{\frac{11}{4}} - 9 x^{\frac{7}{4}} - 2 x^{\frac{3}{4}} - \frac{8}{\sqrt[4]{x}} " data-equation-content=" \displaystyle f(x) = - 9 x^{\frac{11}{4}} - 9 x^{\frac{7}{4}} - 2 x^{\frac{3}{4}} - \frac{8}{\sqrt[4]{x}} " /> . Finding the antiderivative of each term gives <img class="equation_image" title=" \displaystyle F(x) = - \frac{12 x^{\frac{15}{4}}}{5} - \frac{36 x^{\frac{11}{4}}}{11} - \frac{8 x^{\frac{7}{4}}}{7} - \frac{32 x^{\frac{3}{4}}}{3} + C " src="/equation_images/%20%5Cdisplaystyle%20F%28x%29%20%3D%20-%20%5Cfrac%7B12%20x%5E%7B%5Cfrac%7B15%7D%7B4%7D%7D%7D%7B5%7D%20-%20%5Cfrac%7B36%20x%5E%7B%5Cfrac%7B11%7D%7B4%7D%7D%7D%7B11%7D%20-%20%5Cfrac%7B8%20x%5E%7B%5Cfrac%7B7%7D%7B4%7D%7D%7D%7B7%7D%20-%20%5Cfrac%7B32%20x%5E%7B%5Cfrac%7B3%7D%7B4%7D%7D%7D%7B3%7D%20%2B%20C%20" alt="LaTeX: \displaystyle F(x) = - \frac{12 x^{\frac{15}{4}}}{5} - \frac{36 x^{\frac{11}{4}}}{11} - \frac{8 x^{\frac{7}{4}}}{7} - \frac{32 x^{\frac{3}{4}}}{3} + C " data-equation-content=" \displaystyle F(x) = - \frac{12 x^{\frac{15}{4}}}{5} - \frac{36 x^{\frac{11}{4}}}{11} - \frac{8 x^{\frac{7}{4}}}{7} - \frac{32 x^{\frac{3}{4}}}{3} + C " /> </p> </p>