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Two dice are rolled. Find the probability that the sum is greater than 7 or that one die is less than 3.


There are 15 ways the sum is greater than 7. There are 20 ways one die is less than 3. The events are not mutually exclusive and they occur simultaneously 2 times. Using the formula \begin{equation*}P(A \cup B) = P(A) + P(B) - P(A \cap B) = \frac{5}{12} + \frac{5}{9} - \frac{1}{18} = \frac{11}{12}\end{equation*}

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\begin{question}Two dice are rolled. Find the probability that the sum is greater than 7 or that one die is less than 3.
    \soln{9cm}{There are 15 ways the sum is greater than 7. There are 20 ways one die is less than 3. The events are not mutually exclusive and they occur simultaneously 2 times. Using the formula
\begin{equation*}P(A \cup B) = P(A) + P(B) - P(A \cap B) = \frac{5}{12} + \frac{5}{9} - \frac{1}{18} = \frac{11}{12}\end{equation*}
}

\end{question}

Download Question and Solution Environment\(\LaTeX\)
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HTML for Canvas
<p> <p>Two dice are rolled. Find the probability that the sum is greater than 7 or that one die is less than 3.</p> </p>
HTML for Canvas
<p> <p>There are 15 ways the sum is greater than 7. There are 20 ways one die is less than 3. The events are not mutually exclusive and they occur simultaneously 2 times. Using the formula
 <img class="equation_image" title=" P(A \cup B) = P(A) + P(B) - P(A \cap B) = \frac{5}{12} + \frac{5}{9} - \frac{1}{18} = \frac{11}{12} " src="/equation_images/%20P%28A%20%5Ccup%20B%29%20%3D%20P%28A%29%20%2B%20P%28B%29%20-%20P%28A%20%5Ccap%20B%29%20%3D%20%5Cfrac%7B5%7D%7B12%7D%20%2B%20%5Cfrac%7B5%7D%7B9%7D%20-%20%5Cfrac%7B1%7D%7B18%7D%20%3D%20%5Cfrac%7B11%7D%7B12%7D%20" alt="LaTeX:  P(A \cup B) = P(A) + P(B) - P(A \cap B) = \frac{5}{12} + \frac{5}{9} - \frac{1}{18} = \frac{11}{12} " data-equation-content=" P(A \cup B) = P(A) + P(B) - P(A \cap B) = \frac{5}{12} + \frac{5}{9} - \frac{1}{18} = \frac{11}{12} " /> 
</p> </p>