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Questions: Algebra BusinessCalculus
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Find the general term of the sequence \(\displaystyle 4,- \frac{44}{15},\frac{484}{225},\ldots\)
The common ratio is \(\displaystyle r=\frac{a_2}{a_1}=- \frac{11}{15}\). Using the first term and the common ratio gives \(\displaystyle a_n=4\left( - \frac{11}{15} \right)^{n-1}\)
\begin{question}Find the general term of the sequence $4,- \frac{44}{15},\frac{484}{225},\ldots$ \soln{9cm}{The common ratio is $r=\frac{a_2}{a_1}=- \frac{11}{15}$. Using the first term and the common ratio gives $a_n=4\left( - \frac{11}{15} \right)^{n-1}$} \end{question}
\documentclass{article} \usepackage{tikz} \usepackage{amsmath} \usepackage[margin=2cm]{geometry} \usepackage{tcolorbox} \newcounter{ExamNumber} \newcounter{questioncount} \stepcounter{questioncount} \newenvironment{question}{{\noindent\bfseries Question \arabic{questioncount}.}}{\stepcounter{questioncount}} \renewcommand{\labelenumi}{{\bfseries (\alph{enumi})}} \newif\ifShowSolution \newcommand{\soln}[2]{% \ifShowSolution% \noindent\begin{tcolorbox}[colframe=blue,title=Solution]#2\end{tcolorbox}\else% \vspace{#1}% \fi% }% \newcommand{\hideifShowSolution}[1]{% \ifShowSolution% % \else% #1% \fi% }% \everymath{\displaystyle} \ShowSolutiontrue \begin{document}\begin{question}(10pts) The question goes here! \soln{9cm}{The solution goes here.} \end{question}\end{document}
<p> <p>Find the general term of the sequence <img class="equation_image" title=" \displaystyle 4,- \frac{44}{15},\frac{484}{225},\ldots " src="/equation_images/%20%5Cdisplaystyle%204%2C-%20%5Cfrac%7B44%7D%7B15%7D%2C%5Cfrac%7B484%7D%7B225%7D%2C%5Cldots%20" alt="LaTeX: \displaystyle 4,- \frac{44}{15},\frac{484}{225},\ldots " data-equation-content=" \displaystyle 4,- \frac{44}{15},\frac{484}{225},\ldots " /> </p> </p>
<p> <p>The common ratio is <img class="equation_image" title=" \displaystyle r=\frac{a_2}{a_1}=- \frac{11}{15} " src="/equation_images/%20%5Cdisplaystyle%20r%3D%5Cfrac%7Ba_2%7D%7Ba_1%7D%3D-%20%5Cfrac%7B11%7D%7B15%7D%20" alt="LaTeX: \displaystyle r=\frac{a_2}{a_1}=- \frac{11}{15} " data-equation-content=" \displaystyle r=\frac{a_2}{a_1}=- \frac{11}{15} " /> . Using the first term and the common ratio gives <img class="equation_image" title=" \displaystyle a_n=4\left( - \frac{11}{15} \right)^{n-1} " src="/equation_images/%20%5Cdisplaystyle%20a_n%3D4%5Cleft%28%20-%20%5Cfrac%7B11%7D%7B15%7D%20%5Cright%29%5E%7Bn-1%7D%20" alt="LaTeX: \displaystyle a_n=4\left( - \frac{11}{15} \right)^{n-1} " data-equation-content=" \displaystyle a_n=4\left( - \frac{11}{15} \right)^{n-1} " /> </p> </p>