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Questions: Algebra BusinessCalculus

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Find the general term of the sequence \(\displaystyle 6,-72,864,\ldots\)


The common ratio is \(\displaystyle r=\frac{a_2}{a_1}=-12\). Using the first term and the common ratio gives \(\displaystyle a_n=6\left( -12 \right)^{n-1}\)

Download \(\LaTeX\)

\begin{question}Find the general term of the sequence $6,-72,864,\ldots$
    \soln{9cm}{The common ratio is $r=\frac{a_2}{a_1}=-12$. Using the first term and the common ratio gives $a_n=6\left( -12 \right)^{n-1}$}

\end{question}

Download Question and Solution Environment\(\LaTeX\)
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\begin{document}\begin{question}(10pts) The question goes here!
    \soln{9cm}{The solution goes here.}

\end{question}\end{document}
HTML for Canvas
<p> <p>Find the general term of the sequence  <img class="equation_image" title=" \displaystyle 6,-72,864,\ldots " src="/equation_images/%20%5Cdisplaystyle%206%2C-72%2C864%2C%5Cldots%20" alt="LaTeX:  \displaystyle 6,-72,864,\ldots " data-equation-content=" \displaystyle 6,-72,864,\ldots " /> </p> </p>
HTML for Canvas
<p> <p>The common ratio is  <img class="equation_image" title=" \displaystyle r=\frac{a_2}{a_1}=-12 " src="/equation_images/%20%5Cdisplaystyle%20r%3D%5Cfrac%7Ba_2%7D%7Ba_1%7D%3D-12%20" alt="LaTeX:  \displaystyle r=\frac{a_2}{a_1}=-12 " data-equation-content=" \displaystyle r=\frac{a_2}{a_1}=-12 " /> . Using the first term and the common ratio gives  <img class="equation_image" title=" \displaystyle a_n=6\left( -12 \right)^{n-1} " src="/equation_images/%20%5Cdisplaystyle%20a_n%3D6%5Cleft%28%20-12%20%5Cright%29%5E%7Bn-1%7D%20" alt="LaTeX:  \displaystyle a_n=6\left( -12 \right)^{n-1} " data-equation-content=" \displaystyle a_n=6\left( -12 \right)^{n-1} " /> </p> </p>