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Questions: Algebra BusinessCalculus
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Find the horizontal and vertical asymptote(s) of \(\displaystyle f(x) = \frac{x^{2} + 2 x - 80}{2 x^{2} + 12 x + 10}\), if they exist.
The degree of the numerator is the same as the degree of the denominator, so the horizontal asymptote is the ratio of the leading coefficients \(\displaystyle y=\frac{1}{2}\). The vertical asymptotes are the zeros of the denominator. \(\displaystyle 2 x^{2} + 12 x + 10=0 \iff 2 \left(x + 1\right) \left(x + 5\right)=0\). The vertical asymptotes are \(\displaystyle x=-5\) and \(\displaystyle x=-1\).
\begin{question}Find the horizontal and vertical asymptote(s) of $f(x) = \frac{x^{2} + 2 x - 80}{2 x^{2} + 12 x + 10}$, if they exist.
\soln{9cm}{The degree of the numerator is the same as the degree of the denominator, so the horizontal asymptote is the ratio of the leading coefficients $y=\frac{1}{2}$. The vertical asymptotes are the zeros of the denominator. $2 x^{2} + 12 x + 10=0 \iff 2 \left(x + 1\right) \left(x + 5\right)=0$. The vertical asymptotes are $x=-5$ and $x=-1$.}
\end{question}
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\soln{9cm}{The solution goes here.}
\end{question}\end{document}<p> <p>Find the horizontal and vertical asymptote(s) of <img class="equation_image" title=" \displaystyle f(x) = \frac{x^{2} + 2 x - 80}{2 x^{2} + 12 x + 10} " src="/equation_images/%20%5Cdisplaystyle%20f%28x%29%20%3D%20%5Cfrac%7Bx%5E%7B2%7D%20%2B%202%20x%20-%2080%7D%7B2%20x%5E%7B2%7D%20%2B%2012%20x%20%2B%2010%7D%20" alt="LaTeX: \displaystyle f(x) = \frac{x^{2} + 2 x - 80}{2 x^{2} + 12 x + 10} " data-equation-content=" \displaystyle f(x) = \frac{x^{2} + 2 x - 80}{2 x^{2} + 12 x + 10} " /> , if they exist.</p> </p><p> <p>The degree of the numerator is the same as the degree of the denominator, so the horizontal asymptote is the ratio of the leading coefficients <img class="equation_image" title=" \displaystyle y=\frac{1}{2} " src="/equation_images/%20%5Cdisplaystyle%20y%3D%5Cfrac%7B1%7D%7B2%7D%20" alt="LaTeX: \displaystyle y=\frac{1}{2} " data-equation-content=" \displaystyle y=\frac{1}{2} " /> . The vertical asymptotes are the zeros of the denominator. <img class="equation_image" title=" \displaystyle 2 x^{2} + 12 x + 10=0 \iff 2 \left(x + 1\right) \left(x + 5\right)=0 " src="/equation_images/%20%5Cdisplaystyle%202%20x%5E%7B2%7D%20%2B%2012%20x%20%2B%2010%3D0%20%5Ciff%202%20%5Cleft%28x%20%2B%201%5Cright%29%20%5Cleft%28x%20%2B%205%5Cright%29%3D0%20" alt="LaTeX: \displaystyle 2 x^{2} + 12 x + 10=0 \iff 2 \left(x + 1\right) \left(x + 5\right)=0 " data-equation-content=" \displaystyle 2 x^{2} + 12 x + 10=0 \iff 2 \left(x + 1\right) \left(x + 5\right)=0 " /> . The vertical asymptotes are <img class="equation_image" title=" \displaystyle x=-5 " src="/equation_images/%20%5Cdisplaystyle%20x%3D-5%20" alt="LaTeX: \displaystyle x=-5 " data-equation-content=" \displaystyle x=-5 " /> and <img class="equation_image" title=" \displaystyle x=-1 " src="/equation_images/%20%5Cdisplaystyle%20x%3D-1%20" alt="LaTeX: \displaystyle x=-1 " data-equation-content=" \displaystyle x=-1 " /> .</p> </p>