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Find the domain of \(\displaystyle f(x) = \sqrt{- 17 x - 9} - 10\). Write the solution in interval notation.
The domain of a radical function is the solution to the inequality radicand \(\displaystyle \geq 0\). The inequality is \(\displaystyle - 17 x - 9 \geq 0\). Isolating \(\displaystyle x\) gives \(\displaystyle - 17 x \geq 9\) Dividing to finish isolating \(\displaystyle x\) gives \(\displaystyle x \leq - \frac{9}{17}\). The domain is \(\displaystyle \left(-\infty, - \frac{9}{17}\right]\)
\begin{question}Find the domain of $f(x) = \sqrt{- 17 x - 9} - 10$. Write the solution in interval notation. \soln{9cm}{The domain of a radical function is the solution to the inequality radicand $\geq 0$. The inequality is $- 17 x - 9 \geq 0$. Isolating $x$ gives $- 17 x \geq 9$ Dividing to finish isolating $x$ gives $x \leq - \frac{9}{17}$. The domain is $\left(-\infty, - \frac{9}{17}\right]$} \end{question}
\documentclass{article} \usepackage{tikz} \usepackage{amsmath} \usepackage[margin=2cm]{geometry} \usepackage{tcolorbox} \newcounter{ExamNumber} \newcounter{questioncount} \stepcounter{questioncount} \newenvironment{question}{{\noindent\bfseries Question \arabic{questioncount}.}}{\stepcounter{questioncount}} \renewcommand{\labelenumi}{{\bfseries (\alph{enumi})}} \newif\ifShowSolution \newcommand{\soln}[2]{% \ifShowSolution% \noindent\begin{tcolorbox}[colframe=blue,title=Solution]#2\end{tcolorbox}\else% \vspace{#1}% \fi% }% \newcommand{\hideifShowSolution}[1]{% \ifShowSolution% % \else% #1% \fi% }% \everymath{\displaystyle} \ShowSolutiontrue \begin{document}\begin{question}(10pts) The question goes here! \soln{9cm}{The solution goes here.} \end{question}\end{document}
<p> <p>Find the domain of <img class="equation_image" title=" \displaystyle f(x) = \sqrt{- 17 x - 9} - 10 " src="/equation_images/%20%5Cdisplaystyle%20f%28x%29%20%3D%20%5Csqrt%7B-%2017%20x%20-%209%7D%20-%2010%20" alt="LaTeX: \displaystyle f(x) = \sqrt{- 17 x - 9} - 10 " data-equation-content=" \displaystyle f(x) = \sqrt{- 17 x - 9} - 10 " /> . Write the solution in interval notation. </p> </p>
<p> <p>The domain of a radical function is the solution to the inequality radicand <img class="equation_image" title=" \displaystyle \geq 0 " src="/equation_images/%20%5Cdisplaystyle%20%5Cgeq%200%20" alt="LaTeX: \displaystyle \geq 0 " data-equation-content=" \displaystyle \geq 0 " /> . The inequality is <img class="equation_image" title=" \displaystyle - 17 x - 9 \geq 0 " src="/equation_images/%20%5Cdisplaystyle%20-%2017%20x%20-%209%20%5Cgeq%200%20" alt="LaTeX: \displaystyle - 17 x - 9 \geq 0 " data-equation-content=" \displaystyle - 17 x - 9 \geq 0 " /> . Isolating <img class="equation_image" title=" \displaystyle x " src="/equation_images/%20%5Cdisplaystyle%20x%20" alt="LaTeX: \displaystyle x " data-equation-content=" \displaystyle x " /> gives <img class="equation_image" title=" \displaystyle - 17 x \geq 9 " src="/equation_images/%20%5Cdisplaystyle%20-%2017%20x%20%5Cgeq%209%20" alt="LaTeX: \displaystyle - 17 x \geq 9 " data-equation-content=" \displaystyle - 17 x \geq 9 " /> Dividing to finish isolating <img class="equation_image" title=" \displaystyle x " src="/equation_images/%20%5Cdisplaystyle%20x%20" alt="LaTeX: \displaystyle x " data-equation-content=" \displaystyle x " /> gives <img class="equation_image" title=" \displaystyle x \leq - \frac{9}{17} " src="/equation_images/%20%5Cdisplaystyle%20x%20%5Cleq%20-%20%5Cfrac%7B9%7D%7B17%7D%20" alt="LaTeX: \displaystyle x \leq - \frac{9}{17} " data-equation-content=" \displaystyle x \leq - \frac{9}{17} " /> . The domain is <img class="equation_image" title=" \displaystyle \left(-\infty, - \frac{9}{17}\right] " src="/equation_images/%20%5Cdisplaystyle%20%5Cleft%28-%5Cinfty%2C%20-%20%5Cfrac%7B9%7D%7B17%7D%5Cright%5D%20" alt="LaTeX: \displaystyle \left(-\infty, - \frac{9}{17}\right] " data-equation-content=" \displaystyle \left(-\infty, - \frac{9}{17}\right] " /> </p> </p>