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Questions: Algebra BusinessCalculus
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Find the distance between the points \(\displaystyle \left( -57, \ 38\right)\) and \(\displaystyle \left( 3, \ 70\right)\).
The distace formula gives \(\displaystyle d=\sqrt{ ((3)-(-57))^2 + ((70)-(38))^2 }=\sqrt{ 3600 + 1024 }\). Simplifying gives \(\displaystyle d = 68\).
\begin{question}Find the distance between the points $\left( -57, \ 38\right)$ and $\left( 3, \ 70\right)$.
\soln{9cm}{The distace formula gives $d=\sqrt{ ((3)-(-57))^2 + ((70)-(38))^2 }=\sqrt{ 3600 + 1024 }$. Simplifying gives $d = 68$. }
\end{question}
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\begin{document}\begin{question}(10pts) The question goes here!
\soln{9cm}{The solution goes here.}
\end{question}\end{document}<p> <p>Find the distance between the points <img class="equation_image" title=" \displaystyle \left( -57, \ 38\right) " src="/equation_images/%20%5Cdisplaystyle%20%5Cleft%28%20-57%2C%20%5C%20%2038%5Cright%29%20" alt="LaTeX: \displaystyle \left( -57, \ 38\right) " data-equation-content=" \displaystyle \left( -57, \ 38\right) " /> and <img class="equation_image" title=" \displaystyle \left( 3, \ 70\right) " src="/equation_images/%20%5Cdisplaystyle%20%5Cleft%28%203%2C%20%5C%20%2070%5Cright%29%20" alt="LaTeX: \displaystyle \left( 3, \ 70\right) " data-equation-content=" \displaystyle \left( 3, \ 70\right) " /> . </p> </p>
<p> <p>The distace formula gives <img class="equation_image" title=" \displaystyle d=\sqrt{ ((3)-(-57))^2 + ((70)-(38))^2 }=\sqrt{ 3600 + 1024 } " src="/equation_images/%20%5Cdisplaystyle%20d%3D%5Csqrt%7B%20%28%283%29-%28-57%29%29%5E2%20%2B%20%28%2870%29-%2838%29%29%5E2%20%7D%3D%5Csqrt%7B%203600%20%2B%201024%20%7D%20" alt="LaTeX: \displaystyle d=\sqrt{ ((3)-(-57))^2 + ((70)-(38))^2 }=\sqrt{ 3600 + 1024 } " data-equation-content=" \displaystyle d=\sqrt{ ((3)-(-57))^2 + ((70)-(38))^2 }=\sqrt{ 3600 + 1024 } " /> . Simplifying gives <img class="equation_image" title=" \displaystyle d = 68 " src="/equation_images/%20%5Cdisplaystyle%20d%20%3D%2068%20" alt="LaTeX: \displaystyle d = 68 " data-equation-content=" \displaystyle d = 68 " /> . </p> </p>