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Questions: Algebra BusinessCalculus
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Find the center and radius of the circle \(\displaystyle \left(x + 7\right)^{2} + \left(y - 7\right)^{2}=4\).
Using the equation of a circle \(\displaystyle (x-h)^2+(y-k)^2=r^2\) to identify \(\displaystyle h,k,\) and \(\displaystyle r\) gives: \(\displaystyle h=-7\), \(\displaystyle k=7\), and \(\displaystyle r=2\). The center is at \(\displaystyle (-7,7)\) and the radius is \(\displaystyle r = 2\).
\begin{question}Find the center and radius of the circle $\left(x + 7\right)^{2} + \left(y - 7\right)^{2}=4$. \soln{9cm}{Using the equation of a circle $(x-h)^2+(y-k)^2=r^2$ to identify $h,k,$ and $r$ gives: $h=-7$, $k=7$, and $r=2$. The center is at $(-7,7)$ and the radius is $r = 2$. } \end{question}
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<p> <p>Find the center and radius of the circle <img class="equation_image" title=" \displaystyle \left(x + 7\right)^{2} + \left(y - 7\right)^{2}=4 " src="/equation_images/%20%5Cdisplaystyle%20%5Cleft%28x%20%2B%207%5Cright%29%5E%7B2%7D%20%2B%20%5Cleft%28y%20-%207%5Cright%29%5E%7B2%7D%3D4%20" alt="LaTeX: \displaystyle \left(x + 7\right)^{2} + \left(y - 7\right)^{2}=4 " data-equation-content=" \displaystyle \left(x + 7\right)^{2} + \left(y - 7\right)^{2}=4 " /> .</p> </p>
<p> <p>Using the equation of a circle <img class="equation_image" title=" \displaystyle (x-h)^2+(y-k)^2=r^2 " src="/equation_images/%20%5Cdisplaystyle%20%28x-h%29%5E2%2B%28y-k%29%5E2%3Dr%5E2%20" alt="LaTeX: \displaystyle (x-h)^2+(y-k)^2=r^2 " data-equation-content=" \displaystyle (x-h)^2+(y-k)^2=r^2 " /> to identify <img class="equation_image" title=" \displaystyle h,k, " src="/equation_images/%20%5Cdisplaystyle%20h%2Ck%2C%20" alt="LaTeX: \displaystyle h,k, " data-equation-content=" \displaystyle h,k, " /> and <img class="equation_image" title=" \displaystyle r " src="/equation_images/%20%5Cdisplaystyle%20r%20" alt="LaTeX: \displaystyle r " data-equation-content=" \displaystyle r " /> gives: <img class="equation_image" title=" \displaystyle h=-7 " src="/equation_images/%20%5Cdisplaystyle%20h%3D-7%20" alt="LaTeX: \displaystyle h=-7 " data-equation-content=" \displaystyle h=-7 " /> , <img class="equation_image" title=" \displaystyle k=7 " src="/equation_images/%20%5Cdisplaystyle%20k%3D7%20" alt="LaTeX: \displaystyle k=7 " data-equation-content=" \displaystyle k=7 " /> , and <img class="equation_image" title=" \displaystyle r=2 " src="/equation_images/%20%5Cdisplaystyle%20r%3D2%20" alt="LaTeX: \displaystyle r=2 " data-equation-content=" \displaystyle r=2 " /> . The center is at <img class="equation_image" title=" \displaystyle (-7,7) " src="/equation_images/%20%5Cdisplaystyle%20%28-7%2C7%29%20" alt="LaTeX: \displaystyle (-7,7) " data-equation-content=" \displaystyle (-7,7) " /> and the radius is <img class="equation_image" title=" \displaystyle r = 2 " src="/equation_images/%20%5Cdisplaystyle%20r%20%3D%202%20" alt="LaTeX: \displaystyle r = 2 " data-equation-content=" \displaystyle r = 2 " /> . </p> </p>