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Questions: Algebra BusinessCalculus
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Factor \(\displaystyle 45 x^{3} + 54 x^{2} + 20 x + 24\).
Grouping the first two terms and factoring out their GCF, \(\displaystyle 9 x^{2}\), gives \(\displaystyle 9 x^{2}(5 x + 6)\). Grouping the last two terms and factoring out their GCF, \(\displaystyle 4\), gives \(\displaystyle 4(5 x + 6)\). The polynomial now has a common binomial factor of \(\displaystyle 5 x + 6\). This gives \(\displaystyle 9 x^{2} \left(5 x + 6\right) +4 \cdot \left(5 x + 6\right) = \left(5 x + 6\right) \left(9 x^{2} + 4\right)\).
\begin{question}Factor $45 x^{3} + 54 x^{2} + 20 x + 24$.
\soln{9cm}{Grouping the first two terms and factoring out their GCF, $9 x^{2}$, gives $9 x^{2}(5 x + 6)$. Grouping the last two terms and factoring out their GCF, $4$, gives $4(5 x + 6)$. The polynomial now has a common binomial factor of $5 x + 6$. This gives $9 x^{2} \left(5 x + 6\right) +4 \cdot \left(5 x + 6\right) = \left(5 x + 6\right) \left(9 x^{2} + 4\right)$. }
\end{question}
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\begin{document}\begin{question}(10pts) The question goes here!
\soln{9cm}{The solution goes here.}
\end{question}\end{document}<p> <p>Factor <img class="equation_image" title=" \displaystyle 45 x^{3} + 54 x^{2} + 20 x + 24 " src="/equation_images/%20%5Cdisplaystyle%2045%20x%5E%7B3%7D%20%2B%2054%20x%5E%7B2%7D%20%2B%2020%20x%20%2B%2024%20" alt="LaTeX: \displaystyle 45 x^{3} + 54 x^{2} + 20 x + 24 " data-equation-content=" \displaystyle 45 x^{3} + 54 x^{2} + 20 x + 24 " /> . </p> </p><p> <p>Grouping the first two terms and factoring out their GCF, <img class="equation_image" title=" \displaystyle 9 x^{2} " src="/equation_images/%20%5Cdisplaystyle%209%20x%5E%7B2%7D%20" alt="LaTeX: \displaystyle 9 x^{2} " data-equation-content=" \displaystyle 9 x^{2} " /> , gives <img class="equation_image" title=" \displaystyle 9 x^{2}(5 x + 6) " src="/equation_images/%20%5Cdisplaystyle%209%20x%5E%7B2%7D%285%20x%20%2B%206%29%20" alt="LaTeX: \displaystyle 9 x^{2}(5 x + 6) " data-equation-content=" \displaystyle 9 x^{2}(5 x + 6) " /> . Grouping the last two terms and factoring out their GCF, <img class="equation_image" title=" \displaystyle 4 " src="/equation_images/%20%5Cdisplaystyle%204%20" alt="LaTeX: \displaystyle 4 " data-equation-content=" \displaystyle 4 " /> , gives <img class="equation_image" title=" \displaystyle 4(5 x + 6) " src="/equation_images/%20%5Cdisplaystyle%204%285%20x%20%2B%206%29%20" alt="LaTeX: \displaystyle 4(5 x + 6) " data-equation-content=" \displaystyle 4(5 x + 6) " /> . The polynomial now has a common binomial factor of <img class="equation_image" title=" \displaystyle 5 x + 6 " src="/equation_images/%20%5Cdisplaystyle%205%20x%20%2B%206%20" alt="LaTeX: \displaystyle 5 x + 6 " data-equation-content=" \displaystyle 5 x + 6 " /> . This gives <img class="equation_image" title=" \displaystyle 9 x^{2} \left(5 x + 6\right) +4 \cdot \left(5 x + 6\right) = \left(5 x + 6\right) \left(9 x^{2} + 4\right) " src="/equation_images/%20%5Cdisplaystyle%209%20x%5E%7B2%7D%20%5Cleft%285%20x%20%2B%206%5Cright%29%20%2B4%20%5Ccdot%20%5Cleft%285%20x%20%2B%206%5Cright%29%20%3D%20%5Cleft%285%20x%20%2B%206%5Cright%29%20%5Cleft%289%20x%5E%7B2%7D%20%2B%204%5Cright%29%20" alt="LaTeX: \displaystyle 9 x^{2} \left(5 x + 6\right) +4 \cdot \left(5 x + 6\right) = \left(5 x + 6\right) \left(9 x^{2} + 4\right) " data-equation-content=" \displaystyle 9 x^{2} \left(5 x + 6\right) +4 \cdot \left(5 x + 6\right) = \left(5 x + 6\right) \left(9 x^{2} + 4\right) " /> . </p> </p>