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Questions: Algebra BusinessCalculus
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Factor \(\displaystyle 24 x^{3} - 32 x^{2} - 30 x + 40\).
Factoring out the GCF \(\displaystyle 2\) from each term gives \(\displaystyle 2(12 x^{3} - 16 x^{2} - 15 x + 20)\). Grouping the first two terms and factoring out their GCF, \(\displaystyle 4 x^{2}\), gives \(\displaystyle 4 x^{2}(3 x - 4)\). Grouping the last two terms and factoring out their GCF, \(\displaystyle -5\), gives \(\displaystyle -5(3 x - 4)\). The polynomial now has a common binomial factor of \(\displaystyle 3 x - 4\). This gives \(\displaystyle 2[4 x^{2} \left(3 x - 4\right) -5 \cdot \left(3 x - 4\right)] = 2\left(3 x - 4\right) \left(4 x^{2} - 5\right)\).
\begin{question}Factor $24 x^{3} - 32 x^{2} - 30 x + 40$.
\soln{9cm}{Factoring out the GCF $2$ from each term gives $2(12 x^{3} - 16 x^{2} - 15 x + 20)$. Grouping the first two terms and factoring out their GCF, $4 x^{2}$, gives $4 x^{2}(3 x - 4)$. Grouping the last two terms and factoring out their GCF, $-5$, gives $-5(3 x - 4)$. The polynomial now has a common binomial factor of $3 x - 4$. This gives $2[4 x^{2} \left(3 x - 4\right) -5 \cdot \left(3 x - 4\right)] = 2\left(3 x - 4\right) \left(4 x^{2} - 5\right)$. }
\end{question}
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\begin{document}\begin{question}(10pts) The question goes here!
\soln{9cm}{The solution goes here.}
\end{question}\end{document}<p> <p>Factor <img class="equation_image" title=" \displaystyle 24 x^{3} - 32 x^{2} - 30 x + 40 " src="/equation_images/%20%5Cdisplaystyle%2024%20x%5E%7B3%7D%20-%2032%20x%5E%7B2%7D%20-%2030%20x%20%2B%2040%20" alt="LaTeX: \displaystyle 24 x^{3} - 32 x^{2} - 30 x + 40 " data-equation-content=" \displaystyle 24 x^{3} - 32 x^{2} - 30 x + 40 " /> . </p> </p><p> <p>Factoring out the GCF <img class="equation_image" title=" \displaystyle 2 " src="/equation_images/%20%5Cdisplaystyle%202%20" alt="LaTeX: \displaystyle 2 " data-equation-content=" \displaystyle 2 " /> from each term gives <img class="equation_image" title=" \displaystyle 2(12 x^{3} - 16 x^{2} - 15 x + 20) " src="/equation_images/%20%5Cdisplaystyle%202%2812%20x%5E%7B3%7D%20-%2016%20x%5E%7B2%7D%20-%2015%20x%20%2B%2020%29%20" alt="LaTeX: \displaystyle 2(12 x^{3} - 16 x^{2} - 15 x + 20) " data-equation-content=" \displaystyle 2(12 x^{3} - 16 x^{2} - 15 x + 20) " /> . Grouping the first two terms and factoring out their GCF, <img class="equation_image" title=" \displaystyle 4 x^{2} " src="/equation_images/%20%5Cdisplaystyle%204%20x%5E%7B2%7D%20" alt="LaTeX: \displaystyle 4 x^{2} " data-equation-content=" \displaystyle 4 x^{2} " /> , gives <img class="equation_image" title=" \displaystyle 4 x^{2}(3 x - 4) " src="/equation_images/%20%5Cdisplaystyle%204%20x%5E%7B2%7D%283%20x%20-%204%29%20" alt="LaTeX: \displaystyle 4 x^{2}(3 x - 4) " data-equation-content=" \displaystyle 4 x^{2}(3 x - 4) " /> . Grouping the last two terms and factoring out their GCF, <img class="equation_image" title=" \displaystyle -5 " src="/equation_images/%20%5Cdisplaystyle%20-5%20" alt="LaTeX: \displaystyle -5 " data-equation-content=" \displaystyle -5 " /> , gives <img class="equation_image" title=" \displaystyle -5(3 x - 4) " src="/equation_images/%20%5Cdisplaystyle%20-5%283%20x%20-%204%29%20" alt="LaTeX: \displaystyle -5(3 x - 4) " data-equation-content=" \displaystyle -5(3 x - 4) " /> . The polynomial now has a common binomial factor of <img class="equation_image" title=" \displaystyle 3 x - 4 " src="/equation_images/%20%5Cdisplaystyle%203%20x%20-%204%20" alt="LaTeX: \displaystyle 3 x - 4 " data-equation-content=" \displaystyle 3 x - 4 " /> . This gives <img class="equation_image" title=" \displaystyle 2[4 x^{2} \left(3 x - 4\right) -5 \cdot \left(3 x - 4\right)] = 2\left(3 x - 4\right) \left(4 x^{2} - 5\right) " src="/equation_images/%20%5Cdisplaystyle%202%5B4%20x%5E%7B2%7D%20%5Cleft%283%20x%20-%204%5Cright%29%20-5%20%5Ccdot%20%5Cleft%283%20x%20-%204%5Cright%29%5D%20%3D%202%5Cleft%283%20x%20-%204%5Cright%29%20%5Cleft%284%20x%5E%7B2%7D%20-%205%5Cright%29%20" alt="LaTeX: \displaystyle 2[4 x^{2} \left(3 x - 4\right) -5 \cdot \left(3 x - 4\right)] = 2\left(3 x - 4\right) \left(4 x^{2} - 5\right) " data-equation-content=" \displaystyle 2[4 x^{2} \left(3 x - 4\right) -5 \cdot \left(3 x - 4\right)] = 2\left(3 x - 4\right) \left(4 x^{2} - 5\right) " /> . </p> </p>