\(\text{www.the}\beta\text{etafunction.com}\)
Home
Login
Questions: Algebra BusinessCalculus
Please login to create an exam or a quiz.
Factor \(\displaystyle - 36 x^{3} + 8 x^{2} - 54 x + 12\).
Factoring out the GCF \(\displaystyle -2\) from each term gives \(\displaystyle -2(18 x^{3} - 4 x^{2} + 27 x - 6)\). Grouping the first two terms and factoring out their GCF, \(\displaystyle 2 x^{2}\), gives \(\displaystyle 2 x^{2}(9 x - 2)\). Grouping the last two terms and factoring out their GCF, \(\displaystyle 3\), gives \(\displaystyle 3(9 x - 2)\). The polynomial now has a common binomial factor of \(\displaystyle 9 x - 2\). This gives \(\displaystyle -2[2 x^{2} \left(9 x - 2\right) +3 \cdot \left(9 x - 2\right)] = -2\left(9 x - 2\right) \left(2 x^{2} + 3\right)\).
\begin{question}Factor $- 36 x^{3} + 8 x^{2} - 54 x + 12$.
\soln{9cm}{Factoring out the GCF $-2$ from each term gives $-2(18 x^{3} - 4 x^{2} + 27 x - 6)$. Grouping the first two terms and factoring out their GCF, $2 x^{2}$, gives $2 x^{2}(9 x - 2)$. Grouping the last two terms and factoring out their GCF, $3$, gives $3(9 x - 2)$. The polynomial now has a common binomial factor of $9 x - 2$. This gives $-2[2 x^{2} \left(9 x - 2\right) +3 \cdot \left(9 x - 2\right)] = -2\left(9 x - 2\right) \left(2 x^{2} + 3\right)$. }
\end{question}
\documentclass{article}
\usepackage{tikz}
\usepackage{amsmath}
\usepackage[margin=2cm]{geometry}
\usepackage{tcolorbox}
\newcounter{ExamNumber}
\newcounter{questioncount}
\stepcounter{questioncount}
\newenvironment{question}{{\noindent\bfseries Question \arabic{questioncount}.}}{\stepcounter{questioncount}}
\renewcommand{\labelenumi}{{\bfseries (\alph{enumi})}}
\newif\ifShowSolution
\newcommand{\soln}[2]{%
\ifShowSolution%
\noindent\begin{tcolorbox}[colframe=blue,title=Solution]#2\end{tcolorbox}\else%
\vspace{#1}%
\fi%
}%
\newcommand{\hideifShowSolution}[1]{%
\ifShowSolution%
%
\else%
#1%
\fi%
}%
\everymath{\displaystyle}
\ShowSolutiontrue
\begin{document}\begin{question}(10pts) The question goes here!
\soln{9cm}{The solution goes here.}
\end{question}\end{document}<p> <p>Factor <img class="equation_image" title=" \displaystyle - 36 x^{3} + 8 x^{2} - 54 x + 12 " src="/equation_images/%20%5Cdisplaystyle%20-%2036%20x%5E%7B3%7D%20%2B%208%20x%5E%7B2%7D%20-%2054%20x%20%2B%2012%20" alt="LaTeX: \displaystyle - 36 x^{3} + 8 x^{2} - 54 x + 12 " data-equation-content=" \displaystyle - 36 x^{3} + 8 x^{2} - 54 x + 12 " /> . </p> </p><p> <p>Factoring out the GCF <img class="equation_image" title=" \displaystyle -2 " src="/equation_images/%20%5Cdisplaystyle%20-2%20" alt="LaTeX: \displaystyle -2 " data-equation-content=" \displaystyle -2 " /> from each term gives <img class="equation_image" title=" \displaystyle -2(18 x^{3} - 4 x^{2} + 27 x - 6) " src="/equation_images/%20%5Cdisplaystyle%20-2%2818%20x%5E%7B3%7D%20-%204%20x%5E%7B2%7D%20%2B%2027%20x%20-%206%29%20" alt="LaTeX: \displaystyle -2(18 x^{3} - 4 x^{2} + 27 x - 6) " data-equation-content=" \displaystyle -2(18 x^{3} - 4 x^{2} + 27 x - 6) " /> . Grouping the first two terms and factoring out their GCF, <img class="equation_image" title=" \displaystyle 2 x^{2} " src="/equation_images/%20%5Cdisplaystyle%202%20x%5E%7B2%7D%20" alt="LaTeX: \displaystyle 2 x^{2} " data-equation-content=" \displaystyle 2 x^{2} " /> , gives <img class="equation_image" title=" \displaystyle 2 x^{2}(9 x - 2) " src="/equation_images/%20%5Cdisplaystyle%202%20x%5E%7B2%7D%289%20x%20-%202%29%20" alt="LaTeX: \displaystyle 2 x^{2}(9 x - 2) " data-equation-content=" \displaystyle 2 x^{2}(9 x - 2) " /> . Grouping the last two terms and factoring out their GCF, <img class="equation_image" title=" \displaystyle 3 " src="/equation_images/%20%5Cdisplaystyle%203%20" alt="LaTeX: \displaystyle 3 " data-equation-content=" \displaystyle 3 " /> , gives <img class="equation_image" title=" \displaystyle 3(9 x - 2) " src="/equation_images/%20%5Cdisplaystyle%203%289%20x%20-%202%29%20" alt="LaTeX: \displaystyle 3(9 x - 2) " data-equation-content=" \displaystyle 3(9 x - 2) " /> . The polynomial now has a common binomial factor of <img class="equation_image" title=" \displaystyle 9 x - 2 " src="/equation_images/%20%5Cdisplaystyle%209%20x%20-%202%20" alt="LaTeX: \displaystyle 9 x - 2 " data-equation-content=" \displaystyle 9 x - 2 " /> . This gives <img class="equation_image" title=" \displaystyle -2[2 x^{2} \left(9 x - 2\right) +3 \cdot \left(9 x - 2\right)] = -2\left(9 x - 2\right) \left(2 x^{2} + 3\right) " src="/equation_images/%20%5Cdisplaystyle%20-2%5B2%20x%5E%7B2%7D%20%5Cleft%289%20x%20-%202%5Cright%29%20%2B3%20%5Ccdot%20%5Cleft%289%20x%20-%202%5Cright%29%5D%20%3D%20-2%5Cleft%289%20x%20-%202%5Cright%29%20%5Cleft%282%20x%5E%7B2%7D%20%2B%203%5Cright%29%20" alt="LaTeX: \displaystyle -2[2 x^{2} \left(9 x - 2\right) +3 \cdot \left(9 x - 2\right)] = -2\left(9 x - 2\right) \left(2 x^{2} + 3\right) " data-equation-content=" \displaystyle -2[2 x^{2} \left(9 x - 2\right) +3 \cdot \left(9 x - 2\right)] = -2\left(9 x - 2\right) \left(2 x^{2} + 3\right) " /> . </p> </p>