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Solve \(\displaystyle x^{2} - 6 x - 7=0\)
Since \(\displaystyle a=1\) we need to find factors of \(\displaystyle -7\) that add up to \(\displaystyle -6\). The factors are \(\displaystyle -7\) and \(\displaystyle 1\). This gives \(\displaystyle (x - 7)(x + 1)=0\). The solutions are \(\displaystyle x = 7\) and \(\displaystyle x = -1\)
\begin{question}Solve $x^{2} - 6 x - 7=0$ \soln{9cm}{Since $a=1$ we need to find factors of $-7$ that add up to $-6$. The factors are $-7$ and $1$. This gives $(x - 7)(x + 1)=0$. The solutions are $x = 7$ and $x = -1$} \end{question}
\documentclass{article} \usepackage{tikz} \usepackage{amsmath} \usepackage[margin=2cm]{geometry} \usepackage{tcolorbox} \newcounter{ExamNumber} \newcounter{questioncount} \stepcounter{questioncount} \newenvironment{question}{{\noindent\bfseries Question \arabic{questioncount}.}}{\stepcounter{questioncount}} \renewcommand{\labelenumi}{{\bfseries (\alph{enumi})}} \newif\ifShowSolution \newcommand{\soln}[2]{% \ifShowSolution% \noindent\begin{tcolorbox}[colframe=blue,title=Solution]#2\end{tcolorbox}\else% \vspace{#1}% \fi% }% \newcommand{\hideifShowSolution}[1]{% \ifShowSolution% % \else% #1% \fi% }% \everymath{\displaystyle} \ShowSolutiontrue \begin{document}\begin{question}(10pts) The question goes here! \soln{9cm}{The solution goes here.} \end{question}\end{document}
<p> <p>Solve <img class="equation_image" title=" \displaystyle x^{2} - 6 x - 7=0 " src="/equation_images/%20%5Cdisplaystyle%20x%5E%7B2%7D%20-%206%20x%20-%207%3D0%20" alt="LaTeX: \displaystyle x^{2} - 6 x - 7=0 " data-equation-content=" \displaystyle x^{2} - 6 x - 7=0 " /> </p> </p>
<p> <p>Since <img class="equation_image" title=" \displaystyle a=1 " src="/equation_images/%20%5Cdisplaystyle%20a%3D1%20" alt="LaTeX: \displaystyle a=1 " data-equation-content=" \displaystyle a=1 " /> we need to find factors of <img class="equation_image" title=" \displaystyle -7 " src="/equation_images/%20%5Cdisplaystyle%20-7%20" alt="LaTeX: \displaystyle -7 " data-equation-content=" \displaystyle -7 " /> that add up to <img class="equation_image" title=" \displaystyle -6 " src="/equation_images/%20%5Cdisplaystyle%20-6%20" alt="LaTeX: \displaystyle -6 " data-equation-content=" \displaystyle -6 " /> . The factors are <img class="equation_image" title=" \displaystyle -7 " src="/equation_images/%20%5Cdisplaystyle%20-7%20" alt="LaTeX: \displaystyle -7 " data-equation-content=" \displaystyle -7 " /> and <img class="equation_image" title=" \displaystyle 1 " src="/equation_images/%20%5Cdisplaystyle%201%20" alt="LaTeX: \displaystyle 1 " data-equation-content=" \displaystyle 1 " /> . This gives <img class="equation_image" title=" \displaystyle (x - 7)(x + 1)=0 " src="/equation_images/%20%5Cdisplaystyle%20%28x%20-%207%29%28x%20%2B%201%29%3D0%20" alt="LaTeX: \displaystyle (x - 7)(x + 1)=0 " data-equation-content=" \displaystyle (x - 7)(x + 1)=0 " /> . The solutions are <img class="equation_image" title=" \displaystyle x = 7 " src="/equation_images/%20%5Cdisplaystyle%20x%20%3D%207%20" alt="LaTeX: \displaystyle x = 7 " data-equation-content=" \displaystyle x = 7 " /> and <img class="equation_image" title=" \displaystyle x = -1 " src="/equation_images/%20%5Cdisplaystyle%20x%20%3D%20-1%20" alt="LaTeX: \displaystyle x = -1 " data-equation-content=" \displaystyle x = -1 " /> </p> </p>