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Since the lead coefficient is negative factor out $- 1$ . This is an ac method factoring. The factors of $a c = 700$ that add up to $53$ are $25$ and $28$ . Separating gives $(20 x^{2} + 25 x) + (28 x + 35) = 0$ . This gives $- 1 (5 x + 7) (4 x + 5) = 0$ . The solutions are $x = - \frac{7}{5}$ and $x = - \frac{5}{4}$

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L A T E X

\begin{question}Solve $- 20 x^{2} - 53 x - 35=0$
    \soln{9cm}{Since the lead coefficient is negative factor out $-1$. This is an ac method factoring. The factors of $ac = 700$ that add up to $53$ are $25$ and $28$. Separating gives $(20 x^{2} + 25 x)+(28 x + 35)=0$. This gives $-1(5 x + 7)(4 x + 5)=0$. The solutions are $x = - \frac{7}{5}$ and $x = - \frac{5}{4}$}

\end{question}

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L A T E X

\documentclass{article}
\usepackage{tikz}
\usepackage{amsmath}
\usepackage[margin=2cm]{geometry}
\usepackage{tcolorbox}

\newcounter{ExamNumber}
\newcounter{questioncount}
\stepcounter{questioncount}

\newenvironment{question}{{\noindent\bfseries Question \arabic{questioncount}.}}{\stepcounter{questioncount}}
\renewcommand{\labelenumi}{{\bfseries (\alph{enumi})}}

\newif\ifShowSolution
\newcommand{\soln}[2]{%
\ifShowSolution%
\noindent\begin{tcolorbox}[colframe=blue,title=Solution]#2\end{tcolorbox}\else%
\vspace{#1}%
\fi%
}%
\newcommand{\hideifShowSolution}[1]{%
\ifShowSolution%
%
\else%
#1%
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}%
\everymath{\displaystyle}
\ShowSolutiontrue

\begin{document}\begin{question}(10pts) The question goes here!
    \soln{9cm}{The solution goes here.}

\end{question}\end{document}

HTML for Canvas

<p> <p>Solve  <img class="equation_image" title=" \displaystyle - 20 x^{2} - 53 x - 35=0 " src="/equation_images/%20%5Cdisplaystyle%20-%2020%20x%5E%7B2%7D%20-%2053%20x%20-%2035%3D0%20" alt="LaTeX:  \displaystyle - 20 x^{2} - 53 x - 35=0 " data-equation-content=" \displaystyle - 20 x^{2} - 53 x - 35=0 " /> </p> </p>

HTML for Canvas

<p> <p>Since the lead coefficient is negative factor out  <img class="equation_image" title=" \displaystyle -1 " src="/equation_images/%20%5Cdisplaystyle%20-1%20" alt="LaTeX:  \displaystyle -1 " data-equation-content=" \displaystyle -1 " /> . This is an ac method factoring. The factors of  <img class="equation_image" title=" \displaystyle ac = 700 " src="/equation_images/%20%5Cdisplaystyle%20ac%20%3D%20700%20" alt="LaTeX:  \displaystyle ac = 700 " data-equation-content=" \displaystyle ac = 700 " />  that add up to  <img class="equation_image" title=" \displaystyle 53 " src="/equation_images/%20%5Cdisplaystyle%2053%20" alt="LaTeX:  \displaystyle 53 " data-equation-content=" \displaystyle 53 " />  are  <img class="equation_image" title=" \displaystyle 25 " src="/equation_images/%20%5Cdisplaystyle%2025%20" alt="LaTeX:  \displaystyle 25 " data-equation-content=" \displaystyle 25 " />  and  <img class="equation_image" title=" \displaystyle 28 " src="/equation_images/%20%5Cdisplaystyle%2028%20" alt="LaTeX:  \displaystyle 28 " data-equation-content=" \displaystyle 28 " /> . Separating gives  <img class="equation_image" title=" \displaystyle (20 x^{2} + 25 x)+(28 x + 35)=0 " src="/equation_images/%20%5Cdisplaystyle%20%2820%20x%5E%7B2%7D%20%2B%2025%20x%29%2B%2828%20x%20%2B%2035%29%3D0%20" alt="LaTeX:  \displaystyle (20 x^{2} + 25 x)+(28 x + 35)=0 " data-equation-content=" \displaystyle (20 x^{2} + 25 x)+(28 x + 35)=0 " /> . This gives  <img class="equation_image" title=" \displaystyle -1(5 x + 7)(4 x + 5)=0 " src="/equation_images/%20%5Cdisplaystyle%20-1%285%20x%20%2B%207%29%284%20x%20%2B%205%29%3D0%20" alt="LaTeX:  \displaystyle -1(5 x + 7)(4 x + 5)=0 " data-equation-content=" \displaystyle -1(5 x + 7)(4 x + 5)=0 " /> . The solutions are  <img class="equation_image" title=" \displaystyle x = - \frac{7}{5} " src="/equation_images/%20%5Cdisplaystyle%20x%20%3D%20-%20%5Cfrac%7B7%7D%7B5%7D%20" alt="LaTeX:  \displaystyle x = - \frac{7}{5} " data-equation-content=" \displaystyle x = - \frac{7}{5} " />  and  <img class="equation_image" title=" \displaystyle x = - \frac{5}{4} " src="/equation_images/%20%5Cdisplaystyle%20x%20%3D%20-%20%5Cfrac%7B5%7D%7B4%7D%20" alt="LaTeX:  \displaystyle x = - \frac{5}{4} " data-equation-content=" \displaystyle x = - \frac{5}{4} " /> </p> </p>