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Algebra
Logarithms
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Solve \(\displaystyle \log_{ 16 }(x + 20) + \log_{ 16 }(x + 260) = 3\)

Using the product rule for logarithms gives \(\displaystyle \log_{ 16 }(\left(x + 20\right) \left(x + 260\right)) \) and rewriting in exponential form gives \(\displaystyle \left(x + 20\right) \left(x + 260\right) = 4096\) expanding and setting the equation equal to zero gives \(\displaystyle x^{2} + 280 x + 1104 = 0\). Factoring gives \(\displaystyle \left(x + 4\right) \left(x + 276\right)=0\). This gives two possible solutions \(\displaystyle x=-276\) or \(\displaystyle x=-4\). \(\displaystyle x=-276\) is an extraneous solution. The only soution is \(\displaystyle x=-4\).

Download \(\LaTeX\) 

\begin{question}Solve $\log_{ 16 }(x + 20) + \log_{ 16 }(x + 260) = 3$
    \soln{10cm}{Using the product rule for logarithms gives $\log_{ 16 }(\left(x + 20\right) \left(x + 260\right)) $ and rewriting in exponential form gives $\left(x + 20\right) \left(x + 260\right) = 4096$ expanding and setting the equation equal to zero gives $x^{2} + 280 x + 1104 = 0$.  Factoring gives $\left(x + 4\right) \left(x + 276\right)=0$. This gives two possible solutions $x=-276$ or $x=-4$. $x=-276$ is an extraneous solution.  The only soution is $x=-4$. }

\end{question}

Download Question and Solution Environment\(\LaTeX\)
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HTML for Canvas 
<p> <p>Solve  <img class="equation_image" title=" \displaystyle \log_{ 16 }(x + 20) + \log_{ 16 }(x + 260) = 3 " src="/equation_images/%20%5Cdisplaystyle%20%5Clog_%7B%2016%20%7D%28x%20%2B%2020%29%20%2B%20%5Clog_%7B%2016%20%7D%28x%20%2B%20260%29%20%3D%203%20" alt="LaTeX:  \displaystyle \log_{ 16 }(x + 20) + \log_{ 16 }(x + 260) = 3 " data-equation-content=" \displaystyle \log_{ 16 }(x + 20) + \log_{ 16 }(x + 260) = 3 " /> </p> </p>
HTML for Canvas
<p> <p>Using the product rule for logarithms gives  <img class="equation_image" title=" \displaystyle \log_{ 16 }(\left(x + 20\right) \left(x + 260\right))  " src="/equation_images/%20%5Cdisplaystyle%20%5Clog_%7B%2016%20%7D%28%5Cleft%28x%20%2B%2020%5Cright%29%20%5Cleft%28x%20%2B%20260%5Cright%29%29%20%20" alt="LaTeX:  \displaystyle \log_{ 16 }(\left(x + 20\right) \left(x + 260\right))  " data-equation-content=" \displaystyle \log_{ 16 }(\left(x + 20\right) \left(x + 260\right))  " />  and rewriting in exponential form gives  <img class="equation_image" title=" \displaystyle \left(x + 20\right) \left(x + 260\right) = 4096 " src="/equation_images/%20%5Cdisplaystyle%20%5Cleft%28x%20%2B%2020%5Cright%29%20%5Cleft%28x%20%2B%20260%5Cright%29%20%3D%204096%20" alt="LaTeX:  \displaystyle \left(x + 20\right) \left(x + 260\right) = 4096 " data-equation-content=" \displaystyle \left(x + 20\right) \left(x + 260\right) = 4096 " />  expanding and setting the equation equal to zero gives  <img class="equation_image" title=" \displaystyle x^{2} + 280 x + 1104 = 0 " src="/equation_images/%20%5Cdisplaystyle%20x%5E%7B2%7D%20%2B%20280%20x%20%2B%201104%20%3D%200%20" alt="LaTeX:  \displaystyle x^{2} + 280 x + 1104 = 0 " data-equation-content=" \displaystyle x^{2} + 280 x + 1104 = 0 " /> .  Factoring gives  <img class="equation_image" title=" \displaystyle \left(x + 4\right) \left(x + 276\right)=0 " src="/equation_images/%20%5Cdisplaystyle%20%5Cleft%28x%20%2B%204%5Cright%29%20%5Cleft%28x%20%2B%20276%5Cright%29%3D0%20" alt="LaTeX:  \displaystyle \left(x + 4\right) \left(x + 276\right)=0 " data-equation-content=" \displaystyle \left(x + 4\right) \left(x + 276\right)=0 " /> . This gives two possible solutions  <img class="equation_image" title=" \displaystyle x=-276 " src="/equation_images/%20%5Cdisplaystyle%20x%3D-276%20" alt="LaTeX:  \displaystyle x=-276 " data-equation-content=" \displaystyle x=-276 " />  or  <img class="equation_image" title=" \displaystyle x=-4 " src="/equation_images/%20%5Cdisplaystyle%20x%3D-4%20" alt="LaTeX:  \displaystyle x=-4 " data-equation-content=" \displaystyle x=-4 " /> .  <img class="equation_image" title=" \displaystyle x=-276 " src="/equation_images/%20%5Cdisplaystyle%20x%3D-276%20" alt="LaTeX:  \displaystyle x=-276 " data-equation-content=" \displaystyle x=-276 " />  is an extraneous solution.  The only soution is  <img class="equation_image" title=" \displaystyle x=-4 " src="/equation_images/%20%5Cdisplaystyle%20x%3D-4%20" alt="LaTeX:  \displaystyle x=-4 " data-equation-content=" \displaystyle x=-4 " /> . </p> </p>