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Questions: Algebra BusinessCalculus
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Solve \(\displaystyle \log_{ 4 }(x + 6) + \log_{ 4 }(x + 66) = 4\)
Using the product rule for logarithms gives \(\displaystyle \log_{ 4 }(\left(x + 6\right) \left(x + 66\right)) \) and rewriting in exponential form gives \(\displaystyle \left(x + 6\right) \left(x + 66\right) = 256\) expanding and setting the equation equal to zero gives \(\displaystyle x^{2} + 72 x + 140 = 0\). Factoring gives \(\displaystyle \left(x + 2\right) \left(x + 70\right)=0\). This gives two possible solutions \(\displaystyle x=-70\) or \(\displaystyle x=-2\). \(\displaystyle x=-70\) is an extraneous solution. The only soution is \(\displaystyle x=-2\).
\begin{question}Solve $\log_{ 4 }(x + 6) + \log_{ 4 }(x + 66) = 4$
\soln{10cm}{Using the product rule for logarithms gives $\log_{ 4 }(\left(x + 6\right) \left(x + 66\right)) $ and rewriting in exponential form gives $\left(x + 6\right) \left(x + 66\right) = 256$ expanding and setting the equation equal to zero gives $x^{2} + 72 x + 140 = 0$. Factoring gives $\left(x + 2\right) \left(x + 70\right)=0$. This gives two possible solutions $x=-70$ or $x=-2$. $x=-70$ is an extraneous solution. The only soution is $x=-2$. }
\end{question}
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\begin{document}\begin{question}(10pts) The question goes here!
\soln{9cm}{The solution goes here.}
\end{question}\end{document}<p> <p>Solve <img class="equation_image" title=" \displaystyle \log_{ 4 }(x + 6) + \log_{ 4 }(x + 66) = 4 " src="/equation_images/%20%5Cdisplaystyle%20%5Clog_%7B%204%20%7D%28x%20%2B%206%29%20%2B%20%5Clog_%7B%204%20%7D%28x%20%2B%2066%29%20%3D%204%20" alt="LaTeX: \displaystyle \log_{ 4 }(x + 6) + \log_{ 4 }(x + 66) = 4 " data-equation-content=" \displaystyle \log_{ 4 }(x + 6) + \log_{ 4 }(x + 66) = 4 " /> </p> </p><p> <p>Using the product rule for logarithms gives <img class="equation_image" title=" \displaystyle \log_{ 4 }(\left(x + 6\right) \left(x + 66\right)) " src="/equation_images/%20%5Cdisplaystyle%20%5Clog_%7B%204%20%7D%28%5Cleft%28x%20%2B%206%5Cright%29%20%5Cleft%28x%20%2B%2066%5Cright%29%29%20%20" alt="LaTeX: \displaystyle \log_{ 4 }(\left(x + 6\right) \left(x + 66\right)) " data-equation-content=" \displaystyle \log_{ 4 }(\left(x + 6\right) \left(x + 66\right)) " /> and rewriting in exponential form gives <img class="equation_image" title=" \displaystyle \left(x + 6\right) \left(x + 66\right) = 256 " src="/equation_images/%20%5Cdisplaystyle%20%5Cleft%28x%20%2B%206%5Cright%29%20%5Cleft%28x%20%2B%2066%5Cright%29%20%3D%20256%20" alt="LaTeX: \displaystyle \left(x + 6\right) \left(x + 66\right) = 256 " data-equation-content=" \displaystyle \left(x + 6\right) \left(x + 66\right) = 256 " /> expanding and setting the equation equal to zero gives <img class="equation_image" title=" \displaystyle x^{2} + 72 x + 140 = 0 " src="/equation_images/%20%5Cdisplaystyle%20x%5E%7B2%7D%20%2B%2072%20x%20%2B%20140%20%3D%200%20" alt="LaTeX: \displaystyle x^{2} + 72 x + 140 = 0 " data-equation-content=" \displaystyle x^{2} + 72 x + 140 = 0 " /> . Factoring gives <img class="equation_image" title=" \displaystyle \left(x + 2\right) \left(x + 70\right)=0 " src="/equation_images/%20%5Cdisplaystyle%20%5Cleft%28x%20%2B%202%5Cright%29%20%5Cleft%28x%20%2B%2070%5Cright%29%3D0%20" alt="LaTeX: \displaystyle \left(x + 2\right) \left(x + 70\right)=0 " data-equation-content=" \displaystyle \left(x + 2\right) \left(x + 70\right)=0 " /> . This gives two possible solutions <img class="equation_image" title=" \displaystyle x=-70 " src="/equation_images/%20%5Cdisplaystyle%20x%3D-70%20" alt="LaTeX: \displaystyle x=-70 " data-equation-content=" \displaystyle x=-70 " /> or <img class="equation_image" title=" \displaystyle x=-2 " src="/equation_images/%20%5Cdisplaystyle%20x%3D-2%20" alt="LaTeX: \displaystyle x=-2 " data-equation-content=" \displaystyle x=-2 " /> . <img class="equation_image" title=" \displaystyle x=-70 " src="/equation_images/%20%5Cdisplaystyle%20x%3D-70%20" alt="LaTeX: \displaystyle x=-70 " data-equation-content=" \displaystyle x=-70 " /> is an extraneous solution. The only soution is <img class="equation_image" title=" \displaystyle x=-2 " src="/equation_images/%20%5Cdisplaystyle%20x%3D-2%20" alt="LaTeX: \displaystyle x=-2 " data-equation-content=" \displaystyle x=-2 " /> . </p> </p>