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Solve \(\displaystyle \log_{20}(x + 622)+\log_{20}(x + 253) = 4\).

Using logarithmic properties and expanding the argument gives \(\displaystyle \log_{20}(x^{2} + 875 x + 157366)=4\). Making both sides an exponent on the base gives \(\displaystyle x^{2} + 875 x + 157366=20^{4}\). Expanding and setting equal to zero gives \(\displaystyle x^{2} + 875 x - 2634=0\). Factoring gives \(\displaystyle \left(x - 3\right) \left(x + 878\right)=0\). Solving gives the two possible solutions \(\displaystyle x = -878\) and \(\displaystyle x = 3\). The domain of the original is \(\displaystyle \left(-622, \infty\right) \bigcap \left(-253, \infty\right)=\left(-253, \infty\right)\). Checking if each possible solution is in the domain gives: \(\displaystyle x = -878\) is not a solution. \(\displaystyle x=3\) is a solution.

Download \(\LaTeX\) 

\begin{question}Solve $\log_{20}(x + 622)+\log_{20}(x + 253) = 4$. 
    \soln{9cm}{Using logarithmic properties and expanding the argument gives $\log_{20}(x^{2} + 875 x + 157366)=4$. Making both sides an exponent on the base gives $x^{2} + 875 x + 157366=20^{4}$. Expanding and setting equal to zero gives $x^{2} + 875 x - 2634=0$. Factoring gives $\left(x - 3\right) \left(x + 878\right)=0$. Solving gives the two possible solutions $x = -878$ and $x = 3$. The domain of the original is $\left(-622, \infty\right) \bigcap \left(-253, \infty\right)=\left(-253, \infty\right)$.  Checking if each possible solution is in the domain gives: $x = -878$ is not a solution. $x=3$ is a solution. }

\end{question}

Download Question and Solution Environment\(\LaTeX\)
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HTML for Canvas 
<p> <p>Solve  <img class="equation_image" title=" \displaystyle \log_{20}(x + 622)+\log_{20}(x + 253) = 4 " src="/equation_images/%20%5Cdisplaystyle%20%5Clog_%7B20%7D%28x%20%2B%20622%29%2B%5Clog_%7B20%7D%28x%20%2B%20253%29%20%3D%204%20" alt="LaTeX:  \displaystyle \log_{20}(x + 622)+\log_{20}(x + 253) = 4 " data-equation-content=" \displaystyle \log_{20}(x + 622)+\log_{20}(x + 253) = 4 " /> . </p> </p>
HTML for Canvas
<p> <p>Using logarithmic properties and expanding the argument gives  <img class="equation_image" title=" \displaystyle \log_{20}(x^{2} + 875 x + 157366)=4 " src="/equation_images/%20%5Cdisplaystyle%20%5Clog_%7B20%7D%28x%5E%7B2%7D%20%2B%20875%20x%20%2B%20157366%29%3D4%20" alt="LaTeX:  \displaystyle \log_{20}(x^{2} + 875 x + 157366)=4 " data-equation-content=" \displaystyle \log_{20}(x^{2} + 875 x + 157366)=4 " /> . Making both sides an exponent on the base gives  <img class="equation_image" title=" \displaystyle x^{2} + 875 x + 157366=20^{4} " src="/equation_images/%20%5Cdisplaystyle%20x%5E%7B2%7D%20%2B%20875%20x%20%2B%20157366%3D20%5E%7B4%7D%20" alt="LaTeX:  \displaystyle x^{2} + 875 x + 157366=20^{4} " data-equation-content=" \displaystyle x^{2} + 875 x + 157366=20^{4} " /> . Expanding and setting equal to zero gives  <img class="equation_image" title=" \displaystyle x^{2} + 875 x - 2634=0 " src="/equation_images/%20%5Cdisplaystyle%20x%5E%7B2%7D%20%2B%20875%20x%20-%202634%3D0%20" alt="LaTeX:  \displaystyle x^{2} + 875 x - 2634=0 " data-equation-content=" \displaystyle x^{2} + 875 x - 2634=0 " /> . Factoring gives  <img class="equation_image" title=" \displaystyle \left(x - 3\right) \left(x + 878\right)=0 " src="/equation_images/%20%5Cdisplaystyle%20%5Cleft%28x%20-%203%5Cright%29%20%5Cleft%28x%20%2B%20878%5Cright%29%3D0%20" alt="LaTeX:  \displaystyle \left(x - 3\right) \left(x + 878\right)=0 " data-equation-content=" \displaystyle \left(x - 3\right) \left(x + 878\right)=0 " /> . Solving gives the two possible solutions  <img class="equation_image" title=" \displaystyle x = -878 " src="/equation_images/%20%5Cdisplaystyle%20x%20%3D%20-878%20" alt="LaTeX:  \displaystyle x = -878 " data-equation-content=" \displaystyle x = -878 " />  and  <img class="equation_image" title=" \displaystyle x = 3 " src="/equation_images/%20%5Cdisplaystyle%20x%20%3D%203%20" alt="LaTeX:  \displaystyle x = 3 " data-equation-content=" \displaystyle x = 3 " /> . The domain of the original is  <img class="equation_image" title=" \displaystyle \left(-622, \infty\right) \bigcap \left(-253, \infty\right)=\left(-253, \infty\right) " src="/equation_images/%20%5Cdisplaystyle%20%5Cleft%28-622%2C%20%5Cinfty%5Cright%29%20%5Cbigcap%20%5Cleft%28-253%2C%20%5Cinfty%5Cright%29%3D%5Cleft%28-253%2C%20%5Cinfty%5Cright%29%20" alt="LaTeX:  \displaystyle \left(-622, \infty\right) \bigcap \left(-253, \infty\right)=\left(-253, \infty\right) " data-equation-content=" \displaystyle \left(-622, \infty\right) \bigcap \left(-253, \infty\right)=\left(-253, \infty\right) " /> .  Checking if each possible solution is in the domain gives:  <img class="equation_image" title=" \displaystyle x = -878 " src="/equation_images/%20%5Cdisplaystyle%20x%20%3D%20-878%20" alt="LaTeX:  \displaystyle x = -878 " data-equation-content=" \displaystyle x = -878 " />  is not a solution.  <img class="equation_image" title=" \displaystyle x=3 " src="/equation_images/%20%5Cdisplaystyle%20x%3D3%20" alt="LaTeX:  \displaystyle x=3 " data-equation-content=" \displaystyle x=3 " />  is a solution. </p> </p>