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Solve the inequality \(\displaystyle 9 \leq 4 x + 5 < 16\). Write the solution in interval notation.
Since this is a three part inequality we must do the same thing to all three parts.Subtracting 5 from all three parts gives \(\displaystyle 4 \leq 4 x + 5 < 11 \). Dividing off the coefficient of \(\displaystyle x\) gives \(\displaystyle 1 \leq x < \frac{11}{4}\)The solution is \(\displaystyle \big[1,\frac{11}{4}\big)\)
\begin{question}Solve the inequality $9 \leq 4 x + 5 < 16$. Write the solution in interval notation. \newline \soln{9cm}{Since this is a three part inequality we must do the same thing to all three parts.Subtracting 5 from all three parts gives $4 \leq 4 x + 5 < 11 $. Dividing off the coefficient of $x$ gives $1 \leq x < \frac{11}{4}$The solution is $\big[1,\frac{11}{4}\big)$} \end{question}
\documentclass{article} \usepackage{tikz} \usepackage{amsmath} \usepackage[margin=2cm]{geometry} \usepackage{tcolorbox} \newcounter{ExamNumber} \newcounter{questioncount} \stepcounter{questioncount} \newenvironment{question}{{\noindent\bfseries Question \arabic{questioncount}.}}{\stepcounter{questioncount}} \renewcommand{\labelenumi}{{\bfseries (\alph{enumi})}} \newif\ifShowSolution \newcommand{\soln}[2]{% \ifShowSolution% \noindent\begin{tcolorbox}[colframe=blue,title=Solution]#2\end{tcolorbox}\else% \vspace{#1}% \fi% }% \newcommand{\hideifShowSolution}[1]{% \ifShowSolution% % \else% #1% \fi% }% \everymath{\displaystyle} \ShowSolutiontrue \begin{document}\begin{question}(10pts) The question goes here! \soln{9cm}{The solution goes here.} \end{question}\end{document}
<p> <p>Solve the inequality <img class="equation_image" title=" \displaystyle 9 \leq 4 x + 5 < 16 " src="/equation_images/%20%5Cdisplaystyle%209%20%5Cleq%204%20x%20%2B%205%20%3C%2016%20" alt="LaTeX: \displaystyle 9 \leq 4 x + 5 < 16 " data-equation-content=" \displaystyle 9 \leq 4 x + 5 < 16 " /> . Write the solution in interval notation. <br> </p> </p>
<p> <p>Since this is a three part inequality we must do the same thing to all three parts.Subtracting 5 from all three parts gives <img class="equation_image" title=" \displaystyle 4 \leq 4 x + 5 < 11 " src="/equation_images/%20%5Cdisplaystyle%204%20%5Cleq%204%20x%20%2B%205%20%3C%2011%20%20" alt="LaTeX: \displaystyle 4 \leq 4 x + 5 < 11 " data-equation-content=" \displaystyle 4 \leq 4 x + 5 < 11 " /> . Dividing off the coefficient of <img class="equation_image" title=" \displaystyle x " src="/equation_images/%20%5Cdisplaystyle%20x%20" alt="LaTeX: \displaystyle x " data-equation-content=" \displaystyle x " /> gives <img class="equation_image" title=" \displaystyle 1 \leq x < \frac{11}{4} " src="/equation_images/%20%5Cdisplaystyle%201%20%5Cleq%20x%20%3C%20%5Cfrac%7B11%7D%7B4%7D%20" alt="LaTeX: \displaystyle 1 \leq x < \frac{11}{4} " data-equation-content=" \displaystyle 1 \leq x < \frac{11}{4} " /> The solution is <img class="equation_image" title=" \displaystyle \big[1,\frac{11}{4}\big) " src="/equation_images/%20%5Cdisplaystyle%20%5Cbig%5B1%2C%5Cfrac%7B11%7D%7B4%7D%5Cbig%29%20" alt="LaTeX: \displaystyle \big[1,\frac{11}{4}\big) " data-equation-content=" \displaystyle \big[1,\frac{11}{4}\big) " /> </p> </p>