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Questions: Algebra BusinessCalculus
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A 32% alcohol solution is mixed with 390 milliliters of a 44% alcohol solution to make a 38% alcohol mixture. How many milliliters of the 32% alcohol solution were used?
Let \(\displaystyle x\) be the amount of the 32% alcohol solution. This gives the equation \(\displaystyle 0.32(x)+0.44(390)=0.38(x + 390)\). Solving for \(\displaystyle x\) gives 390 milliliters.
\begin{question}A 32\% alcohol solution is mixed with 390 milliliters of a 44\% alcohol solution to make a 38\% alcohol mixture. How many milliliters of the 32\% alcohol solution were used?
\soln{10cm}{Let $x$ be the amount of the 32\% alcohol solution. This gives the equation $0.32(x)+0.44(390)=0.38(x + 390)$. Solving for $x$ gives 390 milliliters.}
\end{question}
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\begin{document}\begin{question}(10pts) The question goes here!
\soln{9cm}{The solution goes here.}
\end{question}\end{document}<p> <p>A 32% alcohol solution is mixed with 390 milliliters of a 44% alcohol solution to make a 38% alcohol mixture. How many milliliters of the 32% alcohol solution were used?</p> </p>
<p> <p>Let <img class="equation_image" title=" \displaystyle x " src="/equation_images/%20%5Cdisplaystyle%20x%20" alt="LaTeX: \displaystyle x " data-equation-content=" \displaystyle x " /> be the amount of the 32% alcohol solution. This gives the equation <img class="equation_image" title=" \displaystyle 0.32(x)+0.44(390)=0.38(x + 390) " src="/equation_images/%20%5Cdisplaystyle%200.32%28x%29%2B0.44%28390%29%3D0.38%28x%20%2B%20390%29%20" alt="LaTeX: \displaystyle 0.32(x)+0.44(390)=0.38(x + 390) " data-equation-content=" \displaystyle 0.32(x)+0.44(390)=0.38(x + 390) " /> . Solving for <img class="equation_image" title=" \displaystyle x " src="/equation_images/%20%5Cdisplaystyle%20x%20" alt="LaTeX: \displaystyle x " data-equation-content=" \displaystyle x " /> gives 390 milliliters.</p> </p>