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Questions: Algebra BusinessCalculus
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$11100 is invested in two different accounts. One account pays 29% simple interest per year and the other account pays 6% simple interest per year. If the total interest earn in one year is $1586.00, how much is invested at each rate?
Let \(\displaystyle x\) be the amount invested at 29%. Then \(\displaystyle 11100-x\) is amount invested at 6%. This gives the equation \(\displaystyle 0.29 x+0.06(11100 - x)=1586\). Solving for \(\displaystyle x\) gives \(\displaystyle x = 4000\). So the amount in the other account is $7100.
\begin{question}\$11100 is invested in two different accounts. One account pays 29\% simple interest per year and the other account pays 6\% simple interest per year. If the total interest earn in one year is \$1586.00, how much is invested at each rate?
\soln{10cm}{Let $x$ be the amount invested at 29\%. Then $11100-x$ is amount invested at 6\%. This gives the equation $0.29 x+0.06(11100 - x)=1586$. Solving for $x$ gives $x = 4000$. So the amount in the other account is \$7100.}
\end{question}
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\soln{9cm}{The solution goes here.}
\end{question}\end{document}<p> <p>$11100 is invested in two different accounts. One account pays 29% simple interest per year and the other account pays 6% simple interest per year. If the total interest earn in one year is $1586.00, how much is invested at each rate? </p> </p>
<p> <p>Let <img class="equation_image" title=" \displaystyle x " src="/equation_images/%20%5Cdisplaystyle%20x%20" alt="LaTeX: \displaystyle x " data-equation-content=" \displaystyle x " /> be the amount invested at 29%. Then <img class="equation_image" title=" \displaystyle 11100-x " src="/equation_images/%20%5Cdisplaystyle%2011100-x%20" alt="LaTeX: \displaystyle 11100-x " data-equation-content=" \displaystyle 11100-x " /> is amount invested at 6%. This gives the equation <img class="equation_image" title=" \displaystyle 0.29 x+0.06(11100 - x)=1586 " src="/equation_images/%20%5Cdisplaystyle%200.29%20x%2B0.06%2811100%20-%20x%29%3D1586%20" alt="LaTeX: \displaystyle 0.29 x+0.06(11100 - x)=1586 " data-equation-content=" \displaystyle 0.29 x+0.06(11100 - x)=1586 " /> . Solving for <img class="equation_image" title=" \displaystyle x " src="/equation_images/%20%5Cdisplaystyle%20x%20" alt="LaTeX: \displaystyle x " data-equation-content=" \displaystyle x " /> gives <img class="equation_image" title=" \displaystyle x = 4000 " src="/equation_images/%20%5Cdisplaystyle%20x%20%3D%204000%20" alt="LaTeX: \displaystyle x = 4000 " data-equation-content=" \displaystyle x = 4000 " /> . So the amount in the other account is $7100.</p> </p>