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Questions: Algebra BusinessCalculus
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$4000 is invested in two different accounts. One account pays 6% simple interest per year and the other account pays 18% simple interest per year. If the total interest earn in one year is $432.00, how much is invested at each rate?
Let \(\displaystyle x\) be the amount invested at 6%. Then \(\displaystyle 4000-x\) is amount invested at 18%. This gives the equation \(\displaystyle 0.06 x+0.18(4000 - x)=432\). Solving for \(\displaystyle x\) gives \(\displaystyle x = 2400\). So the amount in the other account is $1600.
\begin{question}\$4000 is invested in two different accounts. One account pays 6\% simple interest per year and the other account pays 18\% simple interest per year. If the total interest earn in one year is \$432.00, how much is invested at each rate?
\soln{10cm}{Let $x$ be the amount invested at 6\%. Then $4000-x$ is amount invested at 18\%. This gives the equation $0.06 x+0.18(4000 - x)=432$. Solving for $x$ gives $x = 2400$. So the amount in the other account is \$1600.}
\end{question}
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\soln{9cm}{The solution goes here.}
\end{question}\end{document}<p> <p>$4000 is invested in two different accounts. One account pays 6% simple interest per year and the other account pays 18% simple interest per year. If the total interest earn in one year is $432.00, how much is invested at each rate? </p> </p>
<p> <p>Let <img class="equation_image" title=" \displaystyle x " src="/equation_images/%20%5Cdisplaystyle%20x%20" alt="LaTeX: \displaystyle x " data-equation-content=" \displaystyle x " /> be the amount invested at 6%. Then <img class="equation_image" title=" \displaystyle 4000-x " src="/equation_images/%20%5Cdisplaystyle%204000-x%20" alt="LaTeX: \displaystyle 4000-x " data-equation-content=" \displaystyle 4000-x " /> is amount invested at 18%. This gives the equation <img class="equation_image" title=" \displaystyle 0.06 x+0.18(4000 - x)=432 " src="/equation_images/%20%5Cdisplaystyle%200.06%20x%2B0.18%284000%20-%20x%29%3D432%20" alt="LaTeX: \displaystyle 0.06 x+0.18(4000 - x)=432 " data-equation-content=" \displaystyle 0.06 x+0.18(4000 - x)=432 " /> . Solving for <img class="equation_image" title=" \displaystyle x " src="/equation_images/%20%5Cdisplaystyle%20x%20" alt="LaTeX: \displaystyle x " data-equation-content=" \displaystyle x " /> gives <img class="equation_image" title=" \displaystyle x = 2400 " src="/equation_images/%20%5Cdisplaystyle%20x%20%3D%202400%20" alt="LaTeX: \displaystyle x = 2400 " data-equation-content=" \displaystyle x = 2400 " /> . So the amount in the other account is $1600.</p> </p>