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Questions: Algebra BusinessCalculus
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$4800 is invested in two different accounts. One account pays 27% simple interest per year and the other account pays 11% simple interest per year. If the total interest earn in one year is $672.00, how much is invested at each rate?
Let \(\displaystyle x\) be the amount invested at 27%. Then \(\displaystyle 4800-x\) is amount invested at 11%. This gives the equation \(\displaystyle 0.27 x+0.11(4800 - x)=672\). Solving for \(\displaystyle x\) gives \(\displaystyle x = 900\). So the amount in the other account is $3900.
\begin{question}\$4800 is invested in two different accounts. One account pays 27\% simple interest per year and the other account pays 11\% simple interest per year. If the total interest earn in one year is \$672.00, how much is invested at each rate?
\soln{10cm}{Let $x$ be the amount invested at 27\%. Then $4800-x$ is amount invested at 11\%. This gives the equation $0.27 x+0.11(4800 - x)=672$. Solving for $x$ gives $x = 900$. So the amount in the other account is \$3900.}
\end{question}
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\end{question}\end{document}<p> <p>$4800 is invested in two different accounts. One account pays 27% simple interest per year and the other account pays 11% simple interest per year. If the total interest earn in one year is $672.00, how much is invested at each rate? </p> </p>
<p> <p>Let <img class="equation_image" title=" \displaystyle x " src="/equation_images/%20%5Cdisplaystyle%20x%20" alt="LaTeX: \displaystyle x " data-equation-content=" \displaystyle x " /> be the amount invested at 27%. Then <img class="equation_image" title=" \displaystyle 4800-x " src="/equation_images/%20%5Cdisplaystyle%204800-x%20" alt="LaTeX: \displaystyle 4800-x " data-equation-content=" \displaystyle 4800-x " /> is amount invested at 11%. This gives the equation <img class="equation_image" title=" \displaystyle 0.27 x+0.11(4800 - x)=672 " src="/equation_images/%20%5Cdisplaystyle%200.27%20x%2B0.11%284800%20-%20x%29%3D672%20" alt="LaTeX: \displaystyle 0.27 x+0.11(4800 - x)=672 " data-equation-content=" \displaystyle 0.27 x+0.11(4800 - x)=672 " /> . Solving for <img class="equation_image" title=" \displaystyle x " src="/equation_images/%20%5Cdisplaystyle%20x%20" alt="LaTeX: \displaystyle x " data-equation-content=" \displaystyle x " /> gives <img class="equation_image" title=" \displaystyle x = 900 " src="/equation_images/%20%5Cdisplaystyle%20x%20%3D%20900%20" alt="LaTeX: \displaystyle x = 900 " data-equation-content=" \displaystyle x = 900 " /> . So the amount in the other account is $3900.</p> </p>