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Questions: Algebra BusinessCalculus
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Solve \(\displaystyle - 5 x - 1 \geq -9\). Write the solution in interval notation.
Isolating \(\displaystyle x\) gives \(\displaystyle - 5 x\geq-8\). Dividing off the \(\displaystyle x\) coefficient and reversing the inequality symbol because its negative gives \(\displaystyle x\leq\frac{8}{5}\). The solution is \(\displaystyle \left(-\infty, \frac{8}{5}\right]\)
\begin{question}Solve $- 5 x - 1 \geq -9$. Write the solution in interval notation. \soln{9cm}{Isolating $x$ gives $- 5 x\geq-8$. Dividing off the $x$ coefficient and reversing the inequality symbol because its negative gives $x\leq\frac{8}{5}$. The solution is $\left(-\infty, \frac{8}{5}\right]$} \end{question}
\documentclass{article} \usepackage{tikz} \usepackage{amsmath} \usepackage[margin=2cm]{geometry} \usepackage{tcolorbox} \newcounter{ExamNumber} \newcounter{questioncount} \stepcounter{questioncount} \newenvironment{question}{{\noindent\bfseries Question \arabic{questioncount}.}}{\stepcounter{questioncount}} \renewcommand{\labelenumi}{{\bfseries (\alph{enumi})}} \newif\ifShowSolution \newcommand{\soln}[2]{% \ifShowSolution% \noindent\begin{tcolorbox}[colframe=blue,title=Solution]#2\end{tcolorbox}\else% \vspace{#1}% \fi% }% \newcommand{\hideifShowSolution}[1]{% \ifShowSolution% % \else% #1% \fi% }% \everymath{\displaystyle} \ShowSolutiontrue \begin{document}\begin{question}(10pts) The question goes here! \soln{9cm}{The solution goes here.} \end{question}\end{document}
<p> <p>Solve <img class="equation_image" title=" \displaystyle - 5 x - 1 \geq -9 " src="/equation_images/%20%5Cdisplaystyle%20-%205%20x%20-%201%20%5Cgeq%20-9%20" alt="LaTeX: \displaystyle - 5 x - 1 \geq -9 " data-equation-content=" \displaystyle - 5 x - 1 \geq -9 " /> . Write the solution in interval notation. </p> </p>
<p> <p>Isolating <img class="equation_image" title=" \displaystyle x " src="/equation_images/%20%5Cdisplaystyle%20x%20" alt="LaTeX: \displaystyle x " data-equation-content=" \displaystyle x " /> gives <img class="equation_image" title=" \displaystyle - 5 x\geq-8 " src="/equation_images/%20%5Cdisplaystyle%20-%205%20x%5Cgeq-8%20" alt="LaTeX: \displaystyle - 5 x\geq-8 " data-equation-content=" \displaystyle - 5 x\geq-8 " /> . Dividing off the <img class="equation_image" title=" \displaystyle x " src="/equation_images/%20%5Cdisplaystyle%20x%20" alt="LaTeX: \displaystyle x " data-equation-content=" \displaystyle x " /> coefficient and reversing the inequality symbol because its negative gives <img class="equation_image" title=" \displaystyle x\leq\frac{8}{5} " src="/equation_images/%20%5Cdisplaystyle%20x%5Cleq%5Cfrac%7B8%7D%7B5%7D%20" alt="LaTeX: \displaystyle x\leq\frac{8}{5} " data-equation-content=" \displaystyle x\leq\frac{8}{5} " /> . The solution is <img class="equation_image" title=" \displaystyle \left(-\infty, \frac{8}{5}\right] " src="/equation_images/%20%5Cdisplaystyle%20%5Cleft%28-%5Cinfty%2C%20%5Cfrac%7B8%7D%7B5%7D%5Cright%5D%20" alt="LaTeX: \displaystyle \left(-\infty, \frac{8}{5}\right] " data-equation-content=" \displaystyle \left(-\infty, \frac{8}{5}\right] " /> </p> </p>