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Questions: Algebra BusinessCalculus
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On January 4, 1960 the price of a stembolt was $18.60. On January 4, 2009 the price of a stembolt was $17.84. Find the average rate of change in the price of a stembolt from 1960 to 2009. Round to the nearest cent.
The average rate of change is \(\displaystyle \frac{17.84-18.60}{2009-1960}= -0.02\) dollars per year.
\begin{question}On January 4, 1960 the price of a stembolt was \$18.60. On January 4, 2009 the price of a stembolt was \$17.84. Find the average rate of change in the price of a stembolt from 1960 to 2009. Round to the nearest cent.
\soln{9cm}{The average rate of change is $\frac{17.84-18.60}{2009-1960}= -0.02$ dollars per year.}
\end{question}
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\begin{document}\begin{question}(10pts) The question goes here!
\soln{9cm}{The solution goes here.}
\end{question}\end{document}<p> <p>On January 4, 1960 the price of a stembolt was $18.60. On January 4, 2009 the price of a stembolt was $17.84. Find the average rate of change in the price of a stembolt from 1960 to 2009. Round to the nearest cent.</p> </p>
<p> <p>The average rate of change is <img class="equation_image" title=" \displaystyle \frac{17.84-18.60}{2009-1960}= -0.02 " src="/equation_images/%20%5Cdisplaystyle%20%5Cfrac%7B17.84-18.60%7D%7B2009-1960%7D%3D%20-0.02%20" alt="LaTeX: \displaystyle \frac{17.84-18.60}{2009-1960}= -0.02 " data-equation-content=" \displaystyle \frac{17.84-18.60}{2009-1960}= -0.02 " /> dollars per year.</p> </p>