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Questions: Algebra BusinessCalculus
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On January 4, 1989 the price of a stembolt was $33.08. On January 4, 1996 the price of a stembolt was $99.10. Find the average rate of change in the price of a stembolt from 1989 to 1996. Round to the nearest cent.
The average rate of change is \(\displaystyle \frac{99.10-33.08}{1996-1989}= 9.43\) dollars per year.
\begin{question}On January 4, 1989 the price of a stembolt was \$33.08. On January 4, 1996 the price of a stembolt was \$99.10. Find the average rate of change in the price of a stembolt from 1989 to 1996. Round to the nearest cent.
\soln{9cm}{The average rate of change is $\frac{99.10-33.08}{1996-1989}= 9.43$ dollars per year.}
\end{question}
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\begin{document}\begin{question}(10pts) The question goes here!
\soln{9cm}{The solution goes here.}
\end{question}\end{document}<p> <p>On January 4, 1989 the price of a stembolt was $33.08. On January 4, 1996 the price of a stembolt was $99.10. Find the average rate of change in the price of a stembolt from 1989 to 1996. Round to the nearest cent.</p> </p>
<p> <p>The average rate of change is <img class="equation_image" title=" \displaystyle \frac{99.10-33.08}{1996-1989}= 9.43 " src="/equation_images/%20%5Cdisplaystyle%20%5Cfrac%7B99.10-33.08%7D%7B1996-1989%7D%3D%209.43%20" alt="LaTeX: \displaystyle \frac{99.10-33.08}{1996-1989}= 9.43 " data-equation-content=" \displaystyle \frac{99.10-33.08}{1996-1989}= 9.43 " /> dollars per year.</p> </p>