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Questions: Algebra BusinessCalculus
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Use \(\displaystyle h(x) = - 3 x^{2} + 9 x - 8\) to evaluate:
Evaluating the function at \(\displaystyle x = -7\) gives \(\displaystyle f(-7) = - 3 (-7)^{2} + 9 (-7) - 8 = -218\).
Evaluating the function at \(\displaystyle x = - x\) gives \(\displaystyle f(- x) = - 3 (- x)^{2} + 9 (- x) - 8 = - 3 x^{2} - 9 x - 8\).
Evaluating the function at \(\displaystyle x = - t - 3\) gives \(\displaystyle f(- t - 3) = - 3 (- t - 3)^{2} + 9 (- t - 3) - 8 = - 3 t^{2} - 27 t - 62\).
\begin{question}Use $h(x) = - 3 x^{2} + 9 x - 8$ to evaluate:\newline \begin{tabular}{|l|}\hline $h(-7)$ \\ \hline $h(- x)$ \\ \hline $h(- t - 3)$ \\ \hline \end{tabular}\newline \soln{9cm}{Evaluating the function at $x = -7$ gives $f(-7) = - 3 (-7)^{2} + 9 (-7) - 8 = -218$.\newline Evaluating the function at $x = - x$ gives $f(- x) = - 3 (- x)^{2} + 9 (- x) - 8 = - 3 x^{2} - 9 x - 8$.\newline Evaluating the function at $x = - t - 3$ gives $f(- t - 3) = - 3 (- t - 3)^{2} + 9 (- t - 3) - 8 = - 3 t^{2} - 27 t - 62$.\newline } \end{question}
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<p> <p>Use <img class="equation_image" title=" \displaystyle h(x) = - 3 x^{2} + 9 x - 8 " src="/equation_images/%20%5Cdisplaystyle%20h%28x%29%20%3D%20-%203%20x%5E%7B2%7D%20%2B%209%20x%20-%208%20" alt="LaTeX: \displaystyle h(x) = - 3 x^{2} + 9 x - 8 " data-equation-content=" \displaystyle h(x) = - 3 x^{2} + 9 x - 8 " /> to evaluate:<br>
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<p> <p>Evaluating the function at <img class="equation_image" title=" \displaystyle x = -7 " src="/equation_images/%20%5Cdisplaystyle%20x%20%3D%20-7%20" alt="LaTeX: \displaystyle x = -7 " data-equation-content=" \displaystyle x = -7 " /> gives <img class="equation_image" title=" \displaystyle f(-7) = - 3 (-7)^{2} + 9 (-7) - 8 = -218 " src="/equation_images/%20%5Cdisplaystyle%20f%28-7%29%20%3D%20-%203%20%28-7%29%5E%7B2%7D%20%2B%209%20%28-7%29%20-%208%20%3D%20-218%20" alt="LaTeX: \displaystyle f(-7) = - 3 (-7)^{2} + 9 (-7) - 8 = -218 " data-equation-content=" \displaystyle f(-7) = - 3 (-7)^{2} + 9 (-7) - 8 = -218 " /> .<br>
Evaluating the function at <img class="equation_image" title=" \displaystyle x = - x " src="/equation_images/%20%5Cdisplaystyle%20x%20%3D%20-%20x%20" alt="LaTeX: \displaystyle x = - x " data-equation-content=" \displaystyle x = - x " /> gives <img class="equation_image" title=" \displaystyle f(- x) = - 3 (- x)^{2} + 9 (- x) - 8 = - 3 x^{2} - 9 x - 8 " src="/equation_images/%20%5Cdisplaystyle%20f%28-%20x%29%20%3D%20-%203%20%28-%20x%29%5E%7B2%7D%20%2B%209%20%28-%20x%29%20-%208%20%3D%20-%203%20x%5E%7B2%7D%20-%209%20x%20-%208%20" alt="LaTeX: \displaystyle f(- x) = - 3 (- x)^{2} + 9 (- x) - 8 = - 3 x^{2} - 9 x - 8 " data-equation-content=" \displaystyle f(- x) = - 3 (- x)^{2} + 9 (- x) - 8 = - 3 x^{2} - 9 x - 8 " /> .<br>
Evaluating the function at <img class="equation_image" title=" \displaystyle x = - t - 3 " src="/equation_images/%20%5Cdisplaystyle%20x%20%3D%20-%20t%20-%203%20" alt="LaTeX: \displaystyle x = - t - 3 " data-equation-content=" \displaystyle x = - t - 3 " /> gives <img class="equation_image" title=" \displaystyle f(- t - 3) = - 3 (- t - 3)^{2} + 9 (- t - 3) - 8 = - 3 t^{2} - 27 t - 62 " src="/equation_images/%20%5Cdisplaystyle%20f%28-%20t%20-%203%29%20%3D%20-%203%20%28-%20t%20-%203%29%5E%7B2%7D%20%2B%209%20%28-%20t%20-%203%29%20-%208%20%3D%20-%203%20t%5E%7B2%7D%20-%2027%20t%20-%2062%20" alt="LaTeX: \displaystyle f(- t - 3) = - 3 (- t - 3)^{2} + 9 (- t - 3) - 8 = - 3 t^{2} - 27 t - 62 " data-equation-content=" \displaystyle f(- t - 3) = - 3 (- t - 3)^{2} + 9 (- t - 3) - 8 = - 3 t^{2} - 27 t - 62 " /> .<br>
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