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Use translations, reflections, and stretches to graph \(\displaystyle f(x) = - 5 e^{x + 8} - 3\). State the horizontal asymptote and the range of \(\displaystyle f(x)\).


The graph is shifted left 8 units and down 3 units. Since the coefficient is negative the graph is reflected across the \(\displaystyle x-\)axis and stretched by a factor of 5. The horizontal asymptote is \(\displaystyle y= -3\). The range is \(\displaystyle (-\infty, -3)\)

Download Tikz \( \LaTeX \)

\begin{tikzpicture}[scale=.5]
	\draw[very thick, color=blue, opacity=0.3, xstep=1, ystep=1] (-10,-10) grid (10,10);
	\draw[latex-latex, very thick] (-10.4,0)--(10.4,0) node[right]{$x$};
	\draw[latex-latex, very thick] (0,-10.4)--(0,10.4) node[above]{$y$};
	\foreach \x in { -10,-8,...,10 }{
		\pgfmathsetmacro{\xtick}{\x != 0 ? "\x" : ""}
		\draw (\x, .2) -- (\x,-.2) node[below]{$\xtick$};
		}
	\foreach \y in { -10,-8,...,10 }{
		\pgfmathsetmacro{\ytick}{\y != 0 ? "\y" : ""}
		\draw (.2, \y) -- (-.2, \y) node[left]{$\ytick$};
		}
		\draw[very thick, latex-latex, color=blue, samples = 200, domain=-10:-7.7] plot ({\x}, {-5*exp(\x + 8) - 3});
	 \draw[thick, dashed] (-10, -3) -- (10, -3);
\end{tikzpicture}

Download \(\LaTeX\)

\begin{question}Use translations, reflections, and stretches to graph $f(x) = - 5 e^{x + 8} - 3$. State the horizontal asymptote and the range of $f(x)$.\newline 
    \soln{11cm}{The graph is shifted left 8 units and down 3 units. Since the coefficient is negative the graph is reflected across the $x-$axis and stretched by a factor of 5. The horizontal asymptote is $y= -3$. The range is $(-\infty, -3)$\newline\begin{tikzpicture}[scale=.5]
	\draw[very thick, color=blue, opacity=0.3, xstep=1, ystep=1] (-10,-10) grid (10,10);
	\draw[latex-latex, very thick] (-10.4,0)--(10.4,0) node[right]{$x$};
	\draw[latex-latex, very thick] (0,-10.4)--(0,10.4) node[above]{$y$};
	\foreach \x in { -10,-8,...,10 }{
		\pgfmathsetmacro{\xtick}{\x != 0 ? "\x" : ""}
		\draw (\x, .2) -- (\x,-.2) node[below]{$\xtick$};
		}
	\foreach \y in { -10,-8,...,10 }{
		\pgfmathsetmacro{\ytick}{\y != 0 ? "\y" : ""}
		\draw (.2, \y) -- (-.2, \y) node[left]{$\ytick$};
		}
		\draw[very thick, latex-latex, color=blue, samples = 200, domain=-10:-7.7] plot ({\x}, {-5*exp(\x + 8) - 3});
	 \draw[thick, dashed] (-10, -3) -- (10, -3);
\end{tikzpicture}
}

\end{question}

Download Question and Solution Environment\(\LaTeX\)
\documentclass{article}
\usepackage{tikz}
\usepackage{amsmath}
\usepackage[margin=2cm]{geometry}
\usepackage{tcolorbox}

\newcounter{ExamNumber}
\newcounter{questioncount}
\stepcounter{questioncount}

\newenvironment{question}{{\noindent\bfseries Question \arabic{questioncount}.}}{\stepcounter{questioncount}}
\renewcommand{\labelenumi}{{\bfseries (\alph{enumi})}}

\newif\ifShowSolution
\newcommand{\soln}[2]{%
\ifShowSolution%
\noindent\begin{tcolorbox}[colframe=blue,title=Solution]#2\end{tcolorbox}\else%
\vspace{#1}%
\fi%
}%
\newcommand{\hideifShowSolution}[1]{%
\ifShowSolution%
%
\else%
#1%
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}%
\everymath{\displaystyle}
\ShowSolutiontrue

\begin{document}\begin{question}(10pts) The question goes here!
    \soln{9cm}{The solution goes here.}

\end{question}\end{document}
HTML for Canvas
<p> <p>Use translations, reflections, and stretches to graph  <img class="equation_image" title=" \displaystyle f(x) = - 5 e^{x + 8} - 3 " src="/equation_images/%20%5Cdisplaystyle%20f%28x%29%20%3D%20-%205%20e%5E%7Bx%20%2B%208%7D%20-%203%20" alt="LaTeX:  \displaystyle f(x) = - 5 e^{x + 8} - 3 " data-equation-content=" \displaystyle f(x) = - 5 e^{x + 8} - 3 " /> . State the horizontal asymptote and the range of  <img class="equation_image" title=" \displaystyle f(x) " src="/equation_images/%20%5Cdisplaystyle%20f%28x%29%20" alt="LaTeX:  \displaystyle f(x) " data-equation-content=" \displaystyle f(x) " /> .<br> </p> </p>
HTML for Canvas
<p> <p>The graph is shifted left 8 units and down 3 units. Since the coefficient is negative the graph is reflected across the  <img class="equation_image" title=" \displaystyle x- " src="/equation_images/%20%5Cdisplaystyle%20x-%20" alt="LaTeX:  \displaystyle x- " data-equation-content=" \displaystyle x- " /> axis and stretched by a factor of 5. The horizontal asymptote is  <img class="equation_image" title=" \displaystyle y= -3 " src="/equation_images/%20%5Cdisplaystyle%20y%3D%20-3%20" alt="LaTeX:  \displaystyle y= -3 " data-equation-content=" \displaystyle y= -3 " /> . The range is  <img class="equation_image" title=" \displaystyle (-\infty, -3) " src="/equation_images/%20%5Cdisplaystyle%20%28-%5Cinfty%2C%20-3%29%20" alt="LaTeX:  \displaystyle (-\infty, -3) " data-equation-content=" \displaystyle (-\infty, -3) " /> <br><?xml version="1.0" encoding="UTF-8"?>
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