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Questions: Algebra BusinessCalculus

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Algebra
Exponentials
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Solve \(\displaystyle 6^{x} - 13=75\).


Isolating the exponential gives \(\displaystyle 6^{x}=88\). Taking the logarithm of both sides gives \(\displaystyle x = \log_{6}(88)\)

Download \(\LaTeX\)

\begin{question}Solve $6^{x} - 13=75$. 
    \soln{9cm}{Isolating the exponential gives $6^{x}=88$. Taking the logarithm of both sides gives $x = \log_{6}(88)$}

\end{question}

Download Question and Solution Environment\(\LaTeX\)
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\begin{document}\begin{question}(10pts) The question goes here!
    \soln{9cm}{The solution goes here.}

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HTML for Canvas
<p> <p>Solve  <img class="equation_image" title=" \displaystyle 6^{x} - 13=75 " src="/equation_images/%20%5Cdisplaystyle%206%5E%7Bx%7D%20-%2013%3D75%20" alt="LaTeX:  \displaystyle 6^{x} - 13=75 " data-equation-content=" \displaystyle 6^{x} - 13=75 " /> . </p> </p>
HTML for Canvas
<p> <p>Isolating the exponential gives  <img class="equation_image" title=" \displaystyle 6^{x}=88 " src="/equation_images/%20%5Cdisplaystyle%206%5E%7Bx%7D%3D88%20" alt="LaTeX:  \displaystyle 6^{x}=88 " data-equation-content=" \displaystyle 6^{x}=88 " /> . Taking the logarithm of both sides gives  <img class="equation_image" title=" \displaystyle x = \log_{6}(88) " src="/equation_images/%20%5Cdisplaystyle%20x%20%3D%20%5Clog_%7B6%7D%2888%29%20" alt="LaTeX:  \displaystyle x = \log_{6}(88) " data-equation-content=" \displaystyle x = \log_{6}(88) " /> </p> </p>