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Questions: Algebra BusinessCalculus
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Solve \(\displaystyle 6^{x} - 13=75\).
Isolating the exponential gives \(\displaystyle 6^{x}=88\). Taking the logarithm of both sides gives \(\displaystyle x = \log_{6}(88)\)
\begin{question}Solve $6^{x} - 13=75$. \soln{9cm}{Isolating the exponential gives $6^{x}=88$. Taking the logarithm of both sides gives $x = \log_{6}(88)$} \end{question}
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<p> <p>Solve <img class="equation_image" title=" \displaystyle 6^{x} - 13=75 " src="/equation_images/%20%5Cdisplaystyle%206%5E%7Bx%7D%20-%2013%3D75%20" alt="LaTeX: \displaystyle 6^{x} - 13=75 " data-equation-content=" \displaystyle 6^{x} - 13=75 " /> . </p> </p>
<p> <p>Isolating the exponential gives <img class="equation_image" title=" \displaystyle 6^{x}=88 " src="/equation_images/%20%5Cdisplaystyle%206%5E%7Bx%7D%3D88%20" alt="LaTeX: \displaystyle 6^{x}=88 " data-equation-content=" \displaystyle 6^{x}=88 " /> . Taking the logarithm of both sides gives <img class="equation_image" title=" \displaystyle x = \log_{6}(88) " src="/equation_images/%20%5Cdisplaystyle%20x%20%3D%20%5Clog_%7B6%7D%2888%29%20" alt="LaTeX: \displaystyle x = \log_{6}(88) " data-equation-content=" \displaystyle x = \log_{6}(88) " /> </p> </p>