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Questions: Algebra BusinessCalculus
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Solve \(\displaystyle | 12 x + 4 |=188\)
Splitting into two linear equations gives \(\displaystyle 12 x + 4=-188\) and \(\displaystyle 12 x + 4=188\). Solving gives the two solutions \(\displaystyle x=\frac{46}{3}\) and \(\displaystyle x=-16\)
\begin{question}Solve $| 12 x + 4 |=188$
\soln{9cm}{Splitting into two linear equations gives $12 x + 4=-188$ and $12 x + 4=188$. Solving gives the two solutions $x=\frac{46}{3}$ and $x=-16$}
\end{question}
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\begin{document}\begin{question}(10pts) The question goes here!
\soln{9cm}{The solution goes here.}
\end{question}\end{document}<p> <p>Solve <img class="equation_image" title=" \displaystyle | 12 x + 4 |=188 " src="/equation_images/%20%5Cdisplaystyle%20%7C%2012%20x%20%2B%204%20%7C%3D188%20" alt="LaTeX: \displaystyle | 12 x + 4 |=188 " data-equation-content=" \displaystyle | 12 x + 4 |=188 " /> </p> </p>
<p> <p>Splitting into two linear equations gives <img class="equation_image" title=" \displaystyle 12 x + 4=-188 " src="/equation_images/%20%5Cdisplaystyle%2012%20x%20%2B%204%3D-188%20" alt="LaTeX: \displaystyle 12 x + 4=-188 " data-equation-content=" \displaystyle 12 x + 4=-188 " /> and <img class="equation_image" title=" \displaystyle 12 x + 4=188 " src="/equation_images/%20%5Cdisplaystyle%2012%20x%20%2B%204%3D188%20" alt="LaTeX: \displaystyle 12 x + 4=188 " data-equation-content=" \displaystyle 12 x + 4=188 " /> . Solving gives the two solutions <img class="equation_image" title=" \displaystyle x=\frac{46}{3} " src="/equation_images/%20%5Cdisplaystyle%20x%3D%5Cfrac%7B46%7D%7B3%7D%20" alt="LaTeX: \displaystyle x=\frac{46}{3} " data-equation-content=" \displaystyle x=\frac{46}{3} " /> and <img class="equation_image" title=" \displaystyle x=-16 " src="/equation_images/%20%5Cdisplaystyle%20x%3D-16%20" alt="LaTeX: \displaystyle x=-16 " data-equation-content=" \displaystyle x=-16 " /> </p> </p>