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Questions: Algebra BusinessCalculus
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Solve \(\displaystyle | 10 x - 3 |=143\)
Splitting into two linear equations gives \(\displaystyle 10 x - 3=-143\) and \(\displaystyle 10 x - 3=143\). Solving gives the two solutions \(\displaystyle x=\frac{73}{5}\) and \(\displaystyle x=-14\)
\begin{question}Solve $| 10 x - 3 |=143$
\soln{9cm}{Splitting into two linear equations gives $10 x - 3=-143$ and $10 x - 3=143$. Solving gives the two solutions $x=\frac{73}{5}$ and $x=-14$}
\end{question}
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\begin{document}\begin{question}(10pts) The question goes here!
\soln{9cm}{The solution goes here.}
\end{question}\end{document}<p> <p>Solve <img class="equation_image" title=" \displaystyle | 10 x - 3 |=143 " src="/equation_images/%20%5Cdisplaystyle%20%7C%2010%20x%20-%203%20%7C%3D143%20" alt="LaTeX: \displaystyle | 10 x - 3 |=143 " data-equation-content=" \displaystyle | 10 x - 3 |=143 " /> </p> </p>
<p> <p>Splitting into two linear equations gives <img class="equation_image" title=" \displaystyle 10 x - 3=-143 " src="/equation_images/%20%5Cdisplaystyle%2010%20x%20-%203%3D-143%20" alt="LaTeX: \displaystyle 10 x - 3=-143 " data-equation-content=" \displaystyle 10 x - 3=-143 " /> and <img class="equation_image" title=" \displaystyle 10 x - 3=143 " src="/equation_images/%20%5Cdisplaystyle%2010%20x%20-%203%3D143%20" alt="LaTeX: \displaystyle 10 x - 3=143 " data-equation-content=" \displaystyle 10 x - 3=143 " /> . Solving gives the two solutions <img class="equation_image" title=" \displaystyle x=\frac{73}{5} " src="/equation_images/%20%5Cdisplaystyle%20x%3D%5Cfrac%7B73%7D%7B5%7D%20" alt="LaTeX: \displaystyle x=\frac{73}{5} " data-equation-content=" \displaystyle x=\frac{73}{5} " /> and <img class="equation_image" title=" \displaystyle x=-14 " src="/equation_images/%20%5Cdisplaystyle%20x%3D-14%20" alt="LaTeX: \displaystyle x=-14 " data-equation-content=" \displaystyle x=-14 " /> </p> </p>