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Questions: Algebra BusinessCalculus
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Solve \(\displaystyle | 6 x + 2 |=28\)
Splitting into two linear equations gives \(\displaystyle 6 x + 2=-28\) and \(\displaystyle 6 x + 2=28\). Solving gives the two solutions \(\displaystyle x=\frac{13}{3}\) and \(\displaystyle x=-5\)
\begin{question}Solve $| 6 x + 2 |=28$
\soln{9cm}{Splitting into two linear equations gives $6 x + 2=-28$ and $6 x + 2=28$. Solving gives the two solutions $x=\frac{13}{3}$ and $x=-5$}
\end{question}
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\begin{document}\begin{question}(10pts) The question goes here!
\soln{9cm}{The solution goes here.}
\end{question}\end{document}<p> <p>Solve <img class="equation_image" title=" \displaystyle | 6 x + 2 |=28 " src="/equation_images/%20%5Cdisplaystyle%20%7C%206%20x%20%2B%202%20%7C%3D28%20" alt="LaTeX: \displaystyle | 6 x + 2 |=28 " data-equation-content=" \displaystyle | 6 x + 2 |=28 " /> </p> </p>
<p> <p>Splitting into two linear equations gives <img class="equation_image" title=" \displaystyle 6 x + 2=-28 " src="/equation_images/%20%5Cdisplaystyle%206%20x%20%2B%202%3D-28%20" alt="LaTeX: \displaystyle 6 x + 2=-28 " data-equation-content=" \displaystyle 6 x + 2=-28 " /> and <img class="equation_image" title=" \displaystyle 6 x + 2=28 " src="/equation_images/%20%5Cdisplaystyle%206%20x%20%2B%202%3D28%20" alt="LaTeX: \displaystyle 6 x + 2=28 " data-equation-content=" \displaystyle 6 x + 2=28 " /> . Solving gives the two solutions <img class="equation_image" title=" \displaystyle x=\frac{13}{3} " src="/equation_images/%20%5Cdisplaystyle%20x%3D%5Cfrac%7B13%7D%7B3%7D%20" alt="LaTeX: \displaystyle x=\frac{13}{3} " data-equation-content=" \displaystyle x=\frac{13}{3} " /> and <img class="equation_image" title=" \displaystyle x=-5 " src="/equation_images/%20%5Cdisplaystyle%20x%3D-5%20" alt="LaTeX: \displaystyle x=-5 " data-equation-content=" \displaystyle x=-5 " /> </p> </p>